Hello, the answer to point d is as follows. However, I am not sure how we got the exact values for each standard deviation. please explain By using mean() in R, the mean= 206.45, and st() the standard deviation = 66.42. Percentage lies within 3 standard [7.19, 405.71] is 100% Percentage lies within 2 standard deviation [73.61, 339.29] is 95% Percentage lies within 1 standard deviation [140.03, 272.87] is 71.67%
Hello, the answer to point d is as follows. However, I am not sure how we got the exact values for each standard deviation. please explain By using mean() in R, the mean= 206.45, and st() the standard deviation = 66.42. Percentage lies within 3 standard [7.19, 405.71] is 100% Percentage lies within 2 standard deviation [73.61, 339.29] is 95% Percentage lies within 1 standard deviation [140.03, 272.87] is 71.67%
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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Hello,
the answer to point d is as follows. However, I am not sure how we got the exact values for each standard deviation. please explain
By using
- Percentage lies within 3 standard [7.19, 405.71] is 100%
- Percentage lies within 2 standard deviation [73.61, 339.29] is 95%
- Percentage lies within 1 standard deviation [140.03, 272.87] is 71.67%
thank you.
Expert Solution
Step 1
Mean = 206.45
S. D (sigma) = 66.42
Here we us standard normal distribution properties.
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