Area of pipe = 301.7 mm² Erlargement pipe diameter Contraction pipe diameter = Fitting Manometer Manometer H₁ H₂ Mitre 20cm 19cm Elbow 15cm 13cm Short Bend 16cm 15cm Enlargement 16cm 14cm Contraction 20cm 17cm Gate Valve Gauge Reading = 80Pa 26.2 mm 19.48 mm Head Loss H₁-H₂ Vol Time V S 0.10m³ 15 0.10m³ 15 0.10m³ 15 0.10m³ 15 0.10m³ 55555 H 15 Flow Rate m³/s m/s Velocity v²/2g K

Q: Solve problem 3.27

A: Force F= 2573.17lbAngle θ=55.20oExplanation:

Q: Question 2 The device is used to measure a change in temperature. Bars AB and CD are made of A-36…

A: Given Data Initial temperature (Ti) = 40°C  Final temperature (Tf) = 80°C  Member - AB is A-36…

Q: Q Calculates the Force acting on a (2m) square based in the Figure when Pressure gage reads (150…

A: Given:Gage pressure reading = 150kN/m2Required:Force acting on 2m square

Q: (1) (2) (37 4 kips 4 24 ft 24 ft Po=10 kips ↓ 24f+ 12' 12' Wu = 3 kuf Mu= Mu= Pu= 10 kips Mu=

A: As per Bartleby's guidelines we are supposed to answer only first three questions, kindly repost…

Q: 6-106. The bucket of the backhoe and its contents have a weight of 1200 lb and a center of gravity…

A:

Q: Problem 1: Moody's Diagram - Finding the Friction Factor Value You perform a calculation for the…

A: Given data- Reynold's Number- Re=2.5×105, e/D ratio = 0.0002, To Find- The value of friction factor…

Q: Question 2 The device is used to measure a change in temperature. Bars AB and CD are made of A-36…

A: Given Data Initial temperature (Ti) = 40°C  Final temperature (Tf) = 80°C  Member - AB is A-36…

Q: Calculate the horizontal displacement of the roller (D). E = 70 GPa and 1 = 2 x 10³ mm² 20 kN B A 21…

A: Horizontal displacement of roller D

Q: Include all necessary FBD

A: Co-efficient of FrictionThe Coefficient of friction is the measure of the relative surface…

Q: Consider (Figure 1). The cord is attached to the 39-lb block, and the coefficients of static…

A:

Q: in the figure is y² = 3.6x. Figure y dx < 1 of 1 dy

A:

Q: 3.79 Differential pressure is being measured between points A and B in two pipes. In pascals, what…

A: To determine the pressure difference between points A and B.   Given, Pressure at point A = pA…

Q: The clockwise angular velocity of the link AB shown in (Figure 1) is WAB = 3.2 rad/s. Figure 1 of 1…

A:

Q: 2) The above pipe is 2.4 feet long and twists over the whole length of the pipe, what is the angle…

A:

Q: Determine the resultant force acting on the hook Enter the components of the force separated by…

A: A hook under the influence of force F1 and F2 is given. We need to calculate resultant force.

Q: . What is the head loss

A:

Braced cuts

The braced cut is a method of providing lateral support to the soil in foundation trenches, to prevent the trenches from deformation by the caving in of soil and resisting it from moving laterally. During shallow excavation in firm soil, generally, slopes are provided to resist the caving in of soil. During shallow excavation in soft soil and deep excavation, the chances of caving in of soil increase. Hence, it becomes necessary to make a provision to resist the deformation of trenches due to caving in of soil. The braced cut is the method used for such conditions. The excavation using braced cuts is a bit uneconomical as compared to the traditional open-cut excavation method but provides better safety than the cut excavation method.