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Applying variation of parameters to the DE: y" - y = e +e-, we get the following system of equations: uj e + u,e- = 0 u e – uhe- = et +e¯ª What are u1 and u2? (U1 and u2 are functions of x.) -2x O u1 =r - e 2; uz = 4 1 1 -2x. , U2 = 8 %3D 4 U1 8 O u1 = In sin x (e); u2 = sec x (e) = -e"; u2

Applying variation of parameters to the DE: y" - y = e +e-, we get the following system of equations: uj e + u,e- = 0 u e – uhe- = et +e¯ª What are u1 and u2? (U1 and u2 are functions of x.) -2x O u1 =r - e 2; uz = 4 1 1 -2x. , U2 = 8 %3D 4 U1 8 O u1 = In sin x (e); u2 = sec x (e) = -e"; u2

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Applying variation of parameters to the DE: y" - y = e" +e", we get the following system of equations: u e + u,e- = 0 %3D uj e" – uze- = * et +e %3D What are u1 and u2? (u1 and u2 are functions of x.) O u1 = - e-2; uz = -÷e% - a %3D 4 1 e-2a; u2 8. %D O ui 4 8. 4 In sin x (e); u2 = sec x (e-) O u1 %3D O u1 = -e"; u2 = -÷e Next >
Transcribed Image Text:Applying variation of parameters to the DE: y" - y = e" +e", we get the following system of equations: u e + u,e- = 0 %3D uj e" – uze- = * et +e %3D What are u1 and u2? (u1 and u2 are functions of x.) O u1 = - e-2; uz = -÷e% - a %3D 4 1 e-2a; u2 8. %D O ui 4 8. 4 In sin x (e); u2 = sec x (e-) O u1 %3D O u1 = -e"; u2 = -÷e Next >
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