1) The entire graph of a one-to-one function f is given in the figure below. Let f-1 be the inverse of f. 4 1 -4 -3 -2 -1 1 2 4 -1 a) f(-3) = c) -f 2x + dx x=2 b) x=-3

Calculus: Early Transcendentals
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Author:James Stewart
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Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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1a, 1b, 1c

**Educational Content: Inverse Functions and Their Derivatives**

---

**1) Analysis of a One-to-One Function**

The graph below represents the entire graph of a one-to-one function \( f \). The task is to understand and calculate properties related to \( f \) and its inverse \( f^{-1} \).

**Graph Explanation:**

- The graph is plotted on a Cartesian plane, with the x-axis and y-axis marked. The units on both axes range from -4 to 5.
- The graph consists of a blue line that connects three distinct sections with open circles indicating points not included in the graph:
  - The first section starts from an open circle at \((-4, 4)\) and slopes downward to an open circle at \((1, -3)\).
  - There is a small horizontal curve from \((2, -3)\) to around \((4, 0)\).
  - The final section starts from \((4, 0)\) and rises steeply to an open circle at \((5, 4)\).

**Tasks:**

a) Calculate \( f^{-1}(-3) \).

b) Determine the derivative of the inverse function at a specific point: \(\left[ \frac{d}{dx} f^{-1}(x) \right]_{x=-3} = \underline{\hspace{2cm}}\).

c) Evaluate the derivative \(\left[ \frac{d}{dx} f\left(2x + \frac{1}{2}\right) \right]_{x=2} = \underline{\hspace{2cm}}\).

---

For further exploration, consider how the properties of the graph, such as slope and open circles, affect the analysis of the inverse function and its derivatives.
Transcribed Image Text:**Educational Content: Inverse Functions and Their Derivatives** --- **1) Analysis of a One-to-One Function** The graph below represents the entire graph of a one-to-one function \( f \). The task is to understand and calculate properties related to \( f \) and its inverse \( f^{-1} \). **Graph Explanation:** - The graph is plotted on a Cartesian plane, with the x-axis and y-axis marked. The units on both axes range from -4 to 5. - The graph consists of a blue line that connects three distinct sections with open circles indicating points not included in the graph: - The first section starts from an open circle at \((-4, 4)\) and slopes downward to an open circle at \((1, -3)\). - There is a small horizontal curve from \((2, -3)\) to around \((4, 0)\). - The final section starts from \((4, 0)\) and rises steeply to an open circle at \((5, 4)\). **Tasks:** a) Calculate \( f^{-1}(-3) \). b) Determine the derivative of the inverse function at a specific point: \(\left[ \frac{d}{dx} f^{-1}(x) \right]_{x=-3} = \underline{\hspace{2cm}}\). c) Evaluate the derivative \(\left[ \frac{d}{dx} f\left(2x + \frac{1}{2}\right) \right]_{x=2} = \underline{\hspace{2cm}}\). --- For further exploration, consider how the properties of the graph, such as slope and open circles, affect the analysis of the inverse function and its derivatives.
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