1) The entire graph of a one-to-one function f is given in the figure below. Let f-1 be the inverse of f. 4 1 -4 -3 -2 -1 1 2 4 -1 a) f(-3) = c) -f 2x + dx x=2 b) x=-3
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1a, 1b, 1c
![**Educational Content: Inverse Functions and Their Derivatives**
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**1) Analysis of a One-to-One Function**
The graph below represents the entire graph of a one-to-one function \( f \). The task is to understand and calculate properties related to \( f \) and its inverse \( f^{-1} \).
**Graph Explanation:**
- The graph is plotted on a Cartesian plane, with the x-axis and y-axis marked. The units on both axes range from -4 to 5.
- The graph consists of a blue line that connects three distinct sections with open circles indicating points not included in the graph:
- The first section starts from an open circle at \((-4, 4)\) and slopes downward to an open circle at \((1, -3)\).
- There is a small horizontal curve from \((2, -3)\) to around \((4, 0)\).
- The final section starts from \((4, 0)\) and rises steeply to an open circle at \((5, 4)\).
**Tasks:**
a) Calculate \( f^{-1}(-3) \).
b) Determine the derivative of the inverse function at a specific point: \(\left[ \frac{d}{dx} f^{-1}(x) \right]_{x=-3} = \underline{\hspace{2cm}}\).
c) Evaluate the derivative \(\left[ \frac{d}{dx} f\left(2x + \frac{1}{2}\right) \right]_{x=2} = \underline{\hspace{2cm}}\).
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For further exploration, consider how the properties of the graph, such as slope and open circles, affect the analysis of the inverse function and its derivatives.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd7323f76-5a9c-46b6-9930-86cefe6607d1%2Fd967fed6-cf24-47b7-992b-fa2e8a2f4f45%2Fadrwnfp_processed.jpeg&w=3840&q=75)

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