Apply the dynamic programming algorithm discussed in Chapter 7 to fill the given table for a knapsack instance of 7 items having values 10, 5, 15, 7, 6, 18, 3 and sizes 2, 3, 5, 7, 1, 4, 1. The knapsack capacity is C =13. The first row and the first column are already filled. The value of the optimal solution is also given.
Apply the dynamic programming algorithm discussed in Chapter 7 to fill the given table for a knapsack instance of 7 items having values 10, 5, 15, 7, 6, 18, 3 and sizes 2, 3, 5, 7, 1, 4, 1. The knapsack capacity is C =13. The first row and the first column are already filled. The value of the optimal solution is also given.
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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
Transcribed Image Text:A. Apply the dynamic programming algorithm discussed in Chapter 7 to fill the given table for a
knapsack instance of 7 items having values 10, 5, 15, 7, 6, 18, 3 and sizes 2, 3, 5, 7, 1, 4, 1.
The knapsack capacity is C=13. The first row and the first column are already filled. The
value of the optimal solution is also given.
0<j<C=13
0.
1
3 4 5 6 7
8 9
10 11
12
13
00 0000 0000 00
Vi=10, S-2 1 0
V=5, S2=3
2 0
V3=15, S3=5 3 0
V4=7, S4=7
40
Vs=6, Ss=1
50
V-18, S6-4 6 0
V-3, S7=1
70
52
B. A way to find the items forming an optimal solution is to sort the items in decreasing order
according to
where Vi and S; are the value and the size of item i. If there is a sequence of
successive items starting from the item 1 where their total size is equal to C (The knapsack
capacity), then they form an optimal solution. Use this method to find and optimal solution
(indicate its items, total value and total size).
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