Use the greedy algorithm below to solve the activity problem. Suppose the S={a,a.....an) is a set of n activities that wish to use the resource. Each activity a; has a start time s; and a finish time fi, where Activities a; and a; are called compatible if the one starts after the other is finished. It is about to select the maximum-size subset of mutually compatible activities. Solve this problem of activity-selection problem. Is this optimal solution? What is the optimal solution? How can you improve it? i 1 S₁ 0 fi 4 2 1 3 3 3 4 4 5 11 5 5 9 6 10 11

Use the greedy algorithm below to solve the activity problem. Suppose the S={a,a.....an) is a set of n activities that wish to use the resource. Each activity a; has a start time s; and a finish time fi, where Activities a; and a; are called compatible if the one starts after the other is finished. It is about to select the maximum-size subset of mutually compatible activities. Solve this problem of activity-selection problem. Is this optimal solution? What is the optimal solution? How can you improve it? i 1 S₁ 0 fi 4 2 1 3 3 3 4 4 5 11 5 5 9 6 10 11

Computer Networking: A Top-Down Approach (7th Edition)

7th Edition

ISBN:9780133594140

Author:James Kurose, Keith Ross

Publisher:James Kurose, Keith Ross

Chapter1: Computer Networks And The Internet

Section: Chapter Questions

Problem R1RQ: What is the difference between a host and an end system? List several different types of end...

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Question

Use the greedy algorithm below to solve the activity problem. Suppose the
s={a1,a2,...,an} is a set of n activities that wish to use the resource. Each activity a; has
a start time s; and a finish time fi, where Activities a; and a; are called compatible if the
one starts after the other is finished. It is about to select the maximum-size subset of
mutually compatible activities. Solve this problem of activity-selection problem. Is this
optimal solution? What is the optimal solution? How can you improve it?
i
S₁
fi
1
0
4
2
1
3
3
3
4
4
5
11
5
5
9
6
10
11
The greedy algorithm
1 n = s.length
2
min = f[1]
3
k = 1
4
5
6
7
for i = 2 to n
if f[i]<min
min = f[i]
k = i
8
A = {a}
9 for mk to n
10
11
12
13
if s[m] ≥f[k]
A=A U{am}
k=m
return A

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