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AP4.1 The plant transfer function is Gp(s): The closed-loop output is given by 1 H(s): -Q3(s) + 1+ GGp(s) Therefore, with E(s) = Ha(s) - H(s), we have -1 E(s) = -Q3(8), 1+ GGp(s) since Ha(s) = 0. (a) When G(s) = K, we have -1 ess = lim sE(s) 840 1 + KR (b) When G(s) = K/s, we have ess = = R RCs + 1 = GGp(s) 1+ GGp(s) = lim sE(s) = 0. 8-0 -Ha(s).

AP4.1 The plant transfer function is Gp(s): The closed-loop output is given by 1 H(s): -Q3(s) + 1+ GGp(s) Therefore, with E(s) = Ha(s) - H(s), we have -1 E(s) = -Q3(8), 1+ GGp(s) since Ha(s) = 0. (a) When G(s) = K, we have -1 ess = lim sE(s) 840 1 + KR (b) When G(s) = K/s, we have ess = = R RCs + 1 = GGp(s) 1+ GGp(s) = lim sE(s) = 0. 8-0 -Ha(s).

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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AP4.1 The plant transfer function is Gp(s) The closed-loop output is given by 1 H(s) = 1+ GG₂ (s) 23 (8) + Therefore, with E(s) = Ha(s) - H(s), we have -1 E(s) = 1+ GG₂(s) 23(s), since Ha(s) = 0. (a) When G(s) = K, we have ess = lim sE(s) -1 1+ KR 8-0 (b) When G(s) = K/s, we have esslim sE(s) = 0. 8-0 = R RCs + 1 GGp(s) 1+ GGp(s) = -Ha(s).
Transcribed Image Text:AP4.1 The plant transfer function is Gp(s) The closed-loop output is given by 1 H(s) = 1+ GG₂ (s) 23 (8) + Therefore, with E(s) = Ha(s) - H(s), we have -1 E(s) = 1+ GG₂(s) 23(s), since Ha(s) = 0. (a) When G(s) = K, we have ess = lim sE(s) -1 1+ KR 8-0 (b) When G(s) = K/s, we have esslim sE(s) = 0. 8-0 = R RCs + 1 GGp(s) 1+ GGp(s) = -Ha(s).
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