AP4.1 The plant transfer function is Gp(s): The closed-loop output is given by 1 H(s): -Q3(s) + 1+ GGp(s) Therefore, with E(s) = Ha(s) - H(s), we have -1 E(s) = -Q3(8), 1+ GGp(s) since Ha(s) = 0. (a) When G(s) = K, we have -1 ess = lim sE(s) 840 1 + KR (b) When G(s) = K/s, we have ess = = R RCs + 1 = GGp(s) 1+ GGp(s) = lim sE(s) = 0. 8-0 -Ha(s).

The Acme Pole Eliminator Company states in their online catalog that the circuit R₁ R₂ shown on the right can eliminate any realizable pole. Their catalog states "Suppose you have a need to eliminate the pole associated with an input, for example, Vç(s) = K/(s + a). Selecting 1/R₁C = a will eliminate the pole, while the ratio R₂/R₁ can be used to provide any desired negative gain or attenuation to the output." Prove or disprove their claim. Vs(s) Cs Acme pole eliminator Vo(s)

Please provide neat and clean diagram and correct explanation

Please could you use Matlab to solve this question and You must submit the Matlab Simulink blocks you used as well as resulting outputs/plots in your answers. Please view the images attached for the question

Task 5: Lets observe a closed loop system below where we have controller C(s) and system G(s) U(s). C(s) G(s) It is known that controller C(s) and systems G(s) transfer functions are Kp(s+K) C(s) = Y(s) U(s) G(s) and s 5 (s+4)(8+7) It is also known that gain for the Pl-controller is Kp = 7. Y(s) ess= a) What is suitable gain Ky so that controller cancel systems slowest pole K₁ = b) After the pole has been canceled what is the closed loop transfer function? c) What is steady-state error in controlled system, when step signal is used as input, which amplitude is A = 2?

Find the transfer function Y1(s)/R2(s) for the multivariate system in Figure E2.14. Plase explain step by step. Thank you!

Hello Sir.Good Evening. I have a question in my home work related Control System Lesson. The following below is my question.Please advise dan please advise reference too.Thank you so much.

Consider the following block diagram R(S)- K H₂(s) G₁(s) H3(s) H₁(s) G₂(s) -Y(S) a) Simplify the block diagram and obtain the closed loop transfer function T(s) = Y(s)/R(s). 1 1 b) Let H₁ H₂ = 1, H3 = K₁, G₂ = and G₁ Give the necessary and sufficient 8+1 conditions on the parameters K₁ and K leading to the stability of T(s). S

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Q3] Consider the system shown in Figure (2). Design a compensator such that the static velocity error constant K, is 5 sec- without appreciably changing the location of the dominant closed-loop poles. Verify the results of your design. 1.06 R(s) Input Gc(s) Y(s) Output - s(s +1)(s+ 2)