= any Let z(x, y) = dz dt Calculate dx dt dy 9,8 dt 5n -4e* sin(y) where x by first finding & Hint: Recall the chain rule: Question Help: Video dt Now use the chain rule to calculate the following: dz Submit Question AZE dx dy dt dt dz dt tº & y = 5nt. and using the chain rule. Search dx dy (8x de ) + (du) dt dt

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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**Problem Statement:**

Let \( z(x, y) = -4e^x \sin(y) \) where \( x = t^9 \) and \( y = 5\pi t \).

**Objective:**

Calculate \( \frac{dz}{dt} \) by first finding \( \frac{dx}{dt} \) and \( \frac{dy}{dt} \) and using the chain rule.

**Given:**

\[ \frac{dx}{dt} = 9t^8 \]

\[ \frac{dy}{dt} = 5\pi \]

**Task:**

Now use the chain rule to calculate the following:

\[ \frac{dz}{dt} = \]

**Hint:**

Recall the chain rule:

\[ \frac{dz}{dt} = \left( \frac{\partial z}{\partial x} \right) \left( \frac{dx}{dt} \right) + \left( \frac{\partial z}{\partial y} \right) \left( \frac{dy}{dt} \right) \]

**Instructions:**

1. **Calculate Partial Derivatives**:
   - Compute \( \frac{\partial z}{\partial x} \) and \( \frac{\partial z}{\partial y} \).

2. **Apply the Chain Rule**:
   - Use the chain rule formula to find \( \frac{dz}{dt} \) by substituting the necessary derivatives.

3. **Use Given Information**:
   - Use the calculated values of \( \frac{dx}{dt} \) and \( \frac{dy}{dt} \) to complete the process.

**Assistance:**

For additional help, click on the video icon.

**Submission:**

After completing the calculations, press the "Submit Question" button.
Transcribed Image Text:**Problem Statement:** Let \( z(x, y) = -4e^x \sin(y) \) where \( x = t^9 \) and \( y = 5\pi t \). **Objective:** Calculate \( \frac{dz}{dt} \) by first finding \( \frac{dx}{dt} \) and \( \frac{dy}{dt} \) and using the chain rule. **Given:** \[ \frac{dx}{dt} = 9t^8 \] \[ \frac{dy}{dt} = 5\pi \] **Task:** Now use the chain rule to calculate the following: \[ \frac{dz}{dt} = \] **Hint:** Recall the chain rule: \[ \frac{dz}{dt} = \left( \frac{\partial z}{\partial x} \right) \left( \frac{dx}{dt} \right) + \left( \frac{\partial z}{\partial y} \right) \left( \frac{dy}{dt} \right) \] **Instructions:** 1. **Calculate Partial Derivatives**: - Compute \( \frac{\partial z}{\partial x} \) and \( \frac{\partial z}{\partial y} \). 2. **Apply the Chain Rule**: - Use the chain rule formula to find \( \frac{dz}{dt} \) by substituting the necessary derivatives. 3. **Use Given Information**: - Use the calculated values of \( \frac{dx}{dt} \) and \( \frac{dy}{dt} \) to complete the process. **Assistance:** For additional help, click on the video icon. **Submission:** After completing the calculations, press the "Submit Question" button.
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