Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Question
![**Question:**
Use implicit differentiation to find \( \frac{dy}{dx} \).
\[ 4\sqrt{y} - y = 2x \]
**Options:**
- \( \frac{dy}{dx} = \frac{2 - \sqrt{y}}{4y} \)
- \( \frac{dy}{dx} = -\frac{2}{y^2} \)
- \( \frac{dy}{dx} = \frac{2}{y^2} \)
- \( \frac{dy}{dx} = \frac{2 - \sqrt{y}}{2 - \sqrt{y}} \)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F346b36e0-a4d8-47d7-8bd1-1ad776cb1cf3%2Fbecbf394-74c6-41c7-91db-78c32d72e76d%2Fx9d358h_processed.png&w=3840&q=75)
Transcribed Image Text:**Question:**
Use implicit differentiation to find \( \frac{dy}{dx} \).
\[ 4\sqrt{y} - y = 2x \]
**Options:**
- \( \frac{dy}{dx} = \frac{2 - \sqrt{y}}{4y} \)
- \( \frac{dy}{dx} = -\frac{2}{y^2} \)
- \( \frac{dy}{dx} = \frac{2}{y^2} \)
- \( \frac{dy}{dx} = \frac{2 - \sqrt{y}}{2 - \sqrt{y}} \)
Expert Solution
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It is implicit derivative.
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