Answer using slope deflection method only, use the picture below as guide for the formulas. thanksShow your complete solution and draw fbd Determine the reactions of the given beam using slope deflection method. P₁ = 25 kN, P₂ = 25 kN, and w = 35 kN/mP₁P₂WI put2mCRA=RD =MD=2mNumerical answer in 4 decimal places and positive values only:RE=BkN (Downward)kN (Upward)21kN-mKN (Upward)4mDI8m wa 43a 2. SaL+6L3212L²14PL8Pab²L²Mb(b-2a)L²wyLMLLPLLLLbFixed End Moment Formulas12WW[28wa (a²+ 41².4aL)8L2wa ³ (4L-3a)121²Pa²bMa(2b-a)L12:10 33 PL16Pab(L+b)22²3a 1.5aHO1202-a-LMKLLLLLb18W2HAWMABdeflection -0₂-²curve -L-PhumcordEl is constantpositive sign conventionFig. 11-2, Structural Analysis,R.C.Hibbeler 8th edMAB = 2E20A + 0B - 32+ FEM ABMBA= -2E20B +0A-33A(FEM) AB-3+ FEM BASign convention: All clockwise internal moments and end rotation are positive.MBAFor end span with far end pinned or roller supportPmini2EILWFig.11-Sb, Structural Analysis, R.C.Hibbeler, 8th ed3EIMN=[N+ FEMNGeneral FormBMNEF= [20N+0F-34 + FEMNF

A continous beam is loaded as follows:

Answered: Answer using slope deflection method…

Answer using slope deflection method only, use the picture below as guide for the formulas. thanks Show your complete solution and draw fbd

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Concept explainers

Beams

In structural engineering, a beam is a component made of a variety of materials (including steel alloys, and wood) that can resist loads applied laterally to the beam axis. Members, elements, rafters, shafts, and purlins are all terms used to describe beams.

Question

Answer using slope deflection method only, use the picture below as guide for the formulas. thanks
Show your complete solution and draw fbd

Determine the reactions of the given beam using slope deflection method. P₁ = 25 kN, P₂ = 25 kN, and w = 35 kN/m
P₁
P₂
W
I put
2m
C
RA=
RD =
MD=
2m
Numerical answer in 4 decimal places and positive values only:
RE=
B
kN (Downward)
kN (Upward)
21
kN-m
KN (Upward)
4m
D
I
8m

wa 43a 2. SaL+6L3
2
12L²
14
PL
8
Pab²
L²
Mb(b-2a)
L²
wy
L
M
L
L
P
L
L
L
L
b
Fixed End Moment Formulas
12
W
W[2
8
wa (a²+ 41².4aL)
8L2
wa ³ (4L-3a)
121²
Pa²b
Ma(2b-a)
L
12:
10 3
3 PL
16
Pab(L+b)
22²
3a 1.5a
HO
120
2
-a-
L
MK
L
L
L
L
L
b
18
W2
HA
W
MAB
deflection -0₂-²
curve -L-
P
hum
cord
El is constant
positive sign convention
Fig. 11-2, Structural Analysis,R.C.Hibbeler 8th ed
MAB = 2E20A + 0B - 32+ FEM AB
MBA= -2E20B +0A-33
A
(FEM) AB
-3+ FEM BA
Sign convention: All clockwise internal moments and end rotation are positive.
MBA
For end span with far end pinned or roller support
P
mini
2EI
L
W
Fig.11-Sb, Structural Analysis, R.C.Hibbeler, 8th ed
3EI
MN=[N+ FEMN
General Form
B
MNEF= [20N+0F-34 + FEMNF

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