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Answer using slope deflection method only, use the picture below as guide for the formulas. thanks Show your complete solution and draw fbd

Answer using slope deflection method only, use the picture below as guide for the formulas. thanks Show your complete solution and draw fbd

Structural Analysis
Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Answer using slope deflection method only, use the picture below as guide for the formulas. thanks
Show your complete solution and draw fbd

Determine the reactions of the given beam using slope deflection method. P₁ = 25 kN, P₂ = 25 kN, and w = 35 kN/m P₁ P₂ W I put 2m C RA= RD = MD= 2m Numerical answer in 4 decimal places and positive values only: RE= B kN (Downward) kN (Upward) 21 kN-m KN (Upward) 4m D I 8m
Transcribed Image Text:Determine the reactions of the given beam using slope deflection method. P₁ = 25 kN, P₂ = 25 kN, and w = 35 kN/m P₁ P₂ W I put 2m C RA= RD = MD= 2m Numerical answer in 4 decimal places and positive values only: RE= B kN (Downward) kN (Upward) 21 kN-m KN (Upward) 4m D I 8m
wa 43a 2. SaL+6L3 2 12L² 14 PL 8 Pab² L² Mb(b-2a) L² wy L M L L P L L L L b Fixed End Moment Formulas 12 W W[2 8 wa (a²+ 41².4aL) 8L2 wa ³ (4L-3a) 121² Pa²b Ma(2b-a) L 12: 10 3 3 PL 16 Pab(L+b) 22² 3a 1.5a HO 120 2 -a- L MK L L L L L b 18 W2 HA W MAB deflection -0₂-² curve -L- P hum cord El is constant positive sign convention Fig. 11-2, Structural Analysis,R.C.Hibbeler 8th ed MAB = 2E20A + 0B - 32+ FEM AB MBA= -2E20B +0A-33 A (FEM) AB -3+ FEM BA Sign convention: All clockwise internal moments and end rotation are positive. MBA For end span with far end pinned or roller support P mini 2EI L W Fig.11-Sb, Structural Analysis, R.C.Hibbeler, 8th ed 3EI MN=[N+ FEMN General Form B MNEF= [20N+0F-34 + FEMNF
Transcribed Image Text:wa 43a 2. SaL+6L3 2 12L² 14 PL 8 Pab² L² Mb(b-2a) L² wy L M L L P L L L L b Fixed End Moment Formulas 12 W W[2 8 wa (a²+ 41².4aL) 8L2 wa ³ (4L-3a) 121² Pa²b Ma(2b-a) L 12: 10 3 3 PL 16 Pab(L+b) 22² 3a 1.5a HO 120 2 -a- L MK L L L L L b 18 W2 HA W MAB deflection -0₂-² curve -L- P hum cord El is constant positive sign convention Fig. 11-2, Structural Analysis,R.C.Hibbeler 8th ed MAB = 2E20A + 0B - 32+ FEM AB MBA= -2E20B +0A-33 A (FEM) AB -3+ FEM BA Sign convention: All clockwise internal moments and end rotation are positive. MBA For end span with far end pinned or roller support P mini 2EI L W Fig.11-Sb, Structural Analysis, R.C.Hibbeler, 8th ed 3EI MN=[N+ FEMN General Form B MNEF= [20N+0F-34 + FEMNF
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