Answer the following questions. N N-H Compound 1 Compound 2 Identify which compound is expected to have a lower pkg. Compound 1 O Compound 2 Choose the correct explanation for the above observation. O Compound 1 is not aromatic, but when compound 1 is deprotonated, the resulting conjugate base is aromatic. Therefore, deprotonation of compound 1 results in the formation of aromaticity, which renders compound 1 much more acidic than compound 2 (compound 2 is already aromatic even without being deprotonated). O Compound 1 has more hydrogen atoms and hence it is more acidic than compound 2. O Compound 1 is a five membered ring and hence it is more acidic than compound 2. O Compound 1 has two N-H bonds, so it is more acidic than compound 2, which has only one N-H bond.
Answer the following questions. N N-H Compound 1 Compound 2 Identify which compound is expected to have a lower pkg. Compound 1 O Compound 2 Choose the correct explanation for the above observation. O Compound 1 is not aromatic, but when compound 1 is deprotonated, the resulting conjugate base is aromatic. Therefore, deprotonation of compound 1 results in the formation of aromaticity, which renders compound 1 much more acidic than compound 2 (compound 2 is already aromatic even without being deprotonated). O Compound 1 has more hydrogen atoms and hence it is more acidic than compound 2. O Compound 1 is a five membered ring and hence it is more acidic than compound 2. O Compound 1 has two N-H bonds, so it is more acidic than compound 2, which has only one N-H bond.
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![Answer the following questions.
N-H,
H.
Compound 1
Compound 2
Identify which compound is expected to have a lower pK.
O Compound 1
O Compound 2
Choose the correct explanation for the above observation.
O Compound 1 is not aromatic, but when compound 1 is deprotonated, the resulting conjugate base is aromatic.
Therefore, deprotonation of compound 1 results in the formation of aromaticity, which renders compound 1 much
more acidic than compound 2 (compound 2 is already aromatic even without being deprotonated).
O Compound 1 has more hydrogen atoms and hence it is more acidic than compound 2.
O Compound 1 is a five membered ring and hence it is more acidic than compound 2.
O Compound 1 has two N-H bonds, so it is more acidic than compound 2, which has only one N-H bond.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fb2c2bfdd-c795-4c13-bc09-4b743040f0d9%2F97e48794-462a-4d62-9925-4146729c9977%2Fllm8a6d_processed.png&w=3840&q=75)
Transcribed Image Text:Answer the following questions.
N-H,
H.
Compound 1
Compound 2
Identify which compound is expected to have a lower pK.
O Compound 1
O Compound 2
Choose the correct explanation for the above observation.
O Compound 1 is not aromatic, but when compound 1 is deprotonated, the resulting conjugate base is aromatic.
Therefore, deprotonation of compound 1 results in the formation of aromaticity, which renders compound 1 much
more acidic than compound 2 (compound 2 is already aromatic even without being deprotonated).
O Compound 1 has more hydrogen atoms and hence it is more acidic than compound 2.
O Compound 1 is a five membered ring and hence it is more acidic than compound 2.
O Compound 1 has two N-H bonds, so it is more acidic than compound 2, which has only one N-H bond.
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