Water is flowing through a horizontal 6 in. Schedule 40 mild steel pipe at 1 atm and 25°C. The inside diameter and the length of the pipe are 0.154 m and 1500 m, respectively, and the roughness factor is 0.0000457 m. The inlet and outlet conditions are P1 = 20 atm, z1 = 0 m, P2 = 2 atm, and z2 = 100 m. The density of water is 1000 kg/m3 and the viscosity is 0.001kg/(m-sec). Calculate the inlet volumetric flow rate and the pressure drop APf fis given by the Colebrook equation as follows: = 2fLv²/D. The friction factor 1 = -1.7372 In (3.7D* NaevF) 1.255 +
Water is flowing through a horizontal 6 in. Schedule 40 mild steel pipe at 1 atm and 25°C. The inside diameter and the length of the pipe are 0.154 m and 1500 m, respectively, and the roughness factor is 0.0000457 m. The inlet and outlet conditions are P1 = 20 atm, z1 = 0 m, P2 = 2 atm, and z2 = 100 m. The density of water is 1000 kg/m3 and the viscosity is 0.001kg/(m-sec). Calculate the inlet volumetric flow rate and the pressure drop APf fis given by the Colebrook equation as follows: = 2fLv²/D. The friction factor 1 = -1.7372 In (3.7D* NaevF) 1.255 +
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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Transcribed Image Text:Water is flowing through a horizontal 6 in. Schedule 40 mild steel pipe at 1 atm and 25°C. The
inside diameter and the length of the pipe are 0.154 m and 1500 m, respectively, and the
roughness factor is 0.0000457 m. The inlet and outlet conditions are P1 = 20 atm, z1 = 0 m, P2 =
2 atm, and z2 = 100 m. The density of water is 1000 kg/m3 and the viscosity is 0.001kg/(m-sec).
Calculate the inlet volumetric flow rate and the pressure drop APf = 2fLv²/D. The friction factor
f is given by the Colebrook equation as follows:
1
= -1.7372In
1.255
+
3.7D ' NReVf)
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answer should be volumetric flowrate = 0.0610367 m^3/sec and pressure drop = 849.219 kPa
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