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Repeat Example 7.7 for 3-in schedule 40 pipe with water flowing at 8 ft/s and pressure 30 psig throughout.

Repeat Example 7.7 for 3-in schedule 40 pipe with water flowing at 8 ft/s and pressure 30 psig throughout.

Introduction to Chemical Engineering Thermodynamics
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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Answer 7.13 please!

7.7. In Examples 7.3 and 7.4 the analysis was simple because the jet was at right angles to the solid surface. You can observe with a garden hose that such jets, perpendicular to walls or sidewalks, go off radially in all directions, with more or less circular symmetry. You will also observe that there is a region near the jet that is much shallower than the rest, as shown in Fig. 7.23 and described in Sec. 7.5.3. A more interesting and complex problem is the flow of a jet against a flat surface that is not perpendicular to you can also observe this flow with a garden hose. The flow is more or less circularly symmetrical, but much more goes away in the direction away from the hose than in the direction toward the hose. But why does any of it flow back in the direction toward the hose? We can understand this if we replace the three-dimensional problem (circular jet, moving in x, y, and z) directions with a two-dimensional jet (as might issue from a rectangular slot) that is constrained to move only in the x and y directions (by directing it into an open rectangular channel, which prevents flow in the z direction). This flow is sketched in Fig. 7.27. Friction is assumed to be negligible, so from B.E. (ignoring gravity) we see that both streams flowing along the wall must have the same velocity as that in the jet, V₁. In the figure the stream going off to the upper right, (2), is larger than that going to the lower left, (3), in accord with the observation described above. If the flow is frictionless, then there can be no shear stress on the wall, so the resisting force must act normal to the surface as shown. We could attempt to solve for these flows by writing the x and y components of the steady flow momentum balance, but that adds more terms and only makes the analysis harder (try it!). Instead, we choose a new set of axes for our momentum balance, with one axis, the s direction, parallel to the plate and the other, the r direction, perpendicular to the plate, as sketched on Fig. 7.27. We now apply Eq. 7.17 in the s direction, finding
Transcribed Image Text:7.7. In Examples 7.3 and 7.4 the analysis was simple because the jet was at right angles to the solid surface. You can observe with a garden hose that such jets, perpendicular to walls or sidewalks, go off radially in all directions, with more or less circular symmetry. You will also observe that there is a region near the jet that is much shallower than the rest, as shown in Fig. 7.23 and described in Sec. 7.5.3. A more interesting and complex problem is the flow of a jet against a flat surface that is not perpendicular to you can also observe this flow with a garden hose. The flow is more or less circularly symmetrical, but much more goes away in the direction away from the hose than in the direction toward the hose. But why does any of it flow back in the direction toward the hose? We can understand this if we replace the three-dimensional problem (circular jet, moving in x, y, and z) directions with a two-dimensional jet (as might issue from a rectangular slot) that is constrained to move only in the x and y directions (by directing it into an open rectangular channel, which prevents flow in the z direction). This flow is sketched in Fig. 7.27. Friction is assumed to be negligible, so from B.E. (ignoring gravity) we see that both streams flowing along the wall must have the same velocity as that in the jet, V₁. In the figure the stream going off to the upper right, (2), is larger than that going to the lower left, (3), in accord with the observation described above. If the flow is frictionless, then there can be no shear stress on the wall, so the resisting force must act normal to the surface as shown. We could attempt to solve for these flows by writing the x and y components of the steady flow momentum balance, but that adds more terms and only makes the analysis harder (try it!). Instead, we choose a new set of axes for our momentum balance, with one axis, the s direction, parallel to the plate and the other, the r direction, perpendicular to the plate, as sketched on Fig. 7.27. We now apply Eq. 7.17 in the s direction, finding
7.13. Repeat Example 7.7 for 3-in schedule 40 pipe with water flowing at 8 ft/s and pressure 30 psig throughout.
Transcribed Image Text:7.13. Repeat Example 7.7 for 3-in schedule 40 pipe with water flowing at 8 ft/s and pressure 30 psig throughout.
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table row D equals cell 3 space i n end cell row V equals cell 8 space f t divided by s end cell row P equals cell 30 space p s i g end cell end table

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