Answer questions a-c about the Bronsted acid-base reaction below using the identifying letters A-D below each structure. The pka's for the acids of interest are: acetic acid (pka = 4.8), and hydrogen bromide (pka = -9). CH₂- OH A acetic acid Br B bromide + H-Br 12 C acetate CH₂- D hydrogen bromide a) The stronger base is b) Its conjugate acid is c) The species that predominate at equilibrium are (two letters, e.g. ac)

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**Bronsted Acid-Base Reaction Analysis**

In this educational exercise, analyze the Bronsted acid-base reaction using the identifying letters A-D below each molecular structure. The pKa values for the acids of interest are given as follows: 

- Acetic acid (\( \text{pKa} = 4.8 \))
- Hydrogen bromide (\( \text{pKa} = -9 \))

**Structures:**

- **A. Acetic acid:** \( \text{CH}_3\text{COOH} \)
- **B. Bromide:** \( \text{Br}^- \)
- **C. Acetate:** \( \text{CH}_3\text{COO}^- \)
- **D. Hydrogen bromide:** \( \text{HBr} \)

**Reaction Equation:**

\[ \text{A (acetic acid)} + \text{B (bromide)} \rightleftharpoons \text{C (acetate)} + \text{D (hydrogen bromide)} \]

**Questions:**

a) **The stronger base** is: [Answer box]

b) **Its conjugate acid** is: [Answer box]

c) **The species that predominate at equilibrium** are: (two letters, e.g., ac) [Answer box]

The above questions help in understanding the nature of the reactants and products in terms of acid-base chemistry and their equilibrium states.
Transcribed Image Text:**Bronsted Acid-Base Reaction Analysis** In this educational exercise, analyze the Bronsted acid-base reaction using the identifying letters A-D below each molecular structure. The pKa values for the acids of interest are given as follows: - Acetic acid (\( \text{pKa} = 4.8 \)) - Hydrogen bromide (\( \text{pKa} = -9 \)) **Structures:** - **A. Acetic acid:** \( \text{CH}_3\text{COOH} \) - **B. Bromide:** \( \text{Br}^- \) - **C. Acetate:** \( \text{CH}_3\text{COO}^- \) - **D. Hydrogen bromide:** \( \text{HBr} \) **Reaction Equation:** \[ \text{A (acetic acid)} + \text{B (bromide)} \rightleftharpoons \text{C (acetate)} + \text{D (hydrogen bromide)} \] **Questions:** a) **The stronger base** is: [Answer box] b) **Its conjugate acid** is: [Answer box] c) **The species that predominate at equilibrium** are: (two letters, e.g., ac) [Answer box] The above questions help in understanding the nature of the reactants and products in terms of acid-base chemistry and their equilibrium states.
Expert Solution
Step 1: Concept

The negative base-10 logarithm of a solution's acid dissociation constant (Ka) is pKa.

pKa = -log10Ka 

The stronger the acid, the lower the pKa value. Acetic acid, for example, has a pKa of 4.8, and hydrogen bromide has -9

Now -9 is the smaller value, so, HBr is a strong acid. 

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