Predict the position of the equilibrium for the reaction and provide a brief explanation. (The acidic protons are shown in red.) -OH CH₂-0 + 00 CH₂-OH D Reverse direction is favored because C is not well solvated, making C a stronger base than B. Reverse direction is favored because C is not well solvated, making C a weaker base than B. Forward direction is favored because C is not well solvated, making C a weaker base than B. Forward direction is favored because C is not well solvated, making C a stronger base than B.

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ChapterU6: Showtime: Reversible Reactions And Chemical Equilibrium
Section: Chapter Questions
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The image features a chemical equation with a question regarding equilibrium.

**Equation:**
- **Reactants:** 
  - A: A molecule with an OH group attached to a carbon chain
  - B: A molecule featuring a CH₃O⁻ group
- **Products:**
  - C: A molecule similar to A, but with an O⁻ group
  - D: CH₃OH molecule

*Note*: Acidic protons are shown in red.

**Question:**
Predict the position of the equilibrium for the reaction and provide a brief explanation.

**Choices:**
1. Reverse direction is favored because C is not well solvated, making C a stronger base than B.
2. Reverse direction is favored because C is not well solvated, making C a weaker base than B.
3. Forward direction is favored because C is not well solvated, making C a weaker base than B.
4. Forward direction is favored because C is not well solvated, making C a stronger base than B.

**Hint:**
Option to save for later.
Transcribed Image Text:The image features a chemical equation with a question regarding equilibrium. **Equation:** - **Reactants:** - A: A molecule with an OH group attached to a carbon chain - B: A molecule featuring a CH₃O⁻ group - **Products:** - C: A molecule similar to A, but with an O⁻ group - D: CH₃OH molecule *Note*: Acidic protons are shown in red. **Question:** Predict the position of the equilibrium for the reaction and provide a brief explanation. **Choices:** 1. Reverse direction is favored because C is not well solvated, making C a stronger base than B. 2. Reverse direction is favored because C is not well solvated, making C a weaker base than B. 3. Forward direction is favored because C is not well solvated, making C a weaker base than B. 4. Forward direction is favored because C is not well solvated, making C a stronger base than B. **Hint:** Option to save for later.
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