Answer part a & b also answer Part h which is not on the image attached but can you answer part h which is Find v: entire trip from 0 sec to tf sec 1.A car travels down a lonely road at constant velocity 20.0m/s. Suddenly, at t=0, the driver sees a deer in the road. After areaction time t = 1.5 seconds, the driver steps on the brakes and thecar then decelerates (slows down) at constant acceleration withmagnitude 4.00 m/s² before coming to rest at time tf. Below is the velocityv vs. time t graph of the car's motion.eose(e)VR = 1.5 sWhat is the time tf when the car finally comes to rest?What is the car's displacement (in m) at t = 1.0 seconds?What is the car's displacement (in m) at t = 4.0 seconds?At what time t is the car's instantaneous velocity v =5.0 m/s?At what time t is the car 's instantaneous velocity v =10.0 m/s?(f)What is the car's average velocity (in m/s) in the timeinterval between tp and tf (when the car is slowing down)?What is the total displacement (i.e. stopping distance inmeters) between t = 0 and t = tf.

Answered: Answer part a & b also answer Part h…

Answer part a & b also answer Part h which is not on the image attached but can you answer part h which is Find v: entire trip from 0 sec to tf sec

Physics for Scientists and Engineers: Foundations and Connections

1st Edition

ISBN:9781133939146

Author:Katz, Debora M.

Publisher:Katz, Debora M.

Chapter2: One Dimensional Motion

Section: Chapter Questions

Problem 30PQ: A The instantaneous speed of a particle moving along one straight line is v(t) = ate5t, where the...

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Concept explainers

Applications Of Reflection Of Light

When a light ray (termed as the incident ray) hits a surface and bounces back (forms a reflected ray), the process of reflection of light has taken place.

Sign Convention for Mirrors

A mirror is made of glass that is coated with a metal amalgam on one side due to which the light ray incident on the surface undergoes reflection and not refraction.

Question

Answer part a & b also answer Part h which is not on the image attached but can you answer part h which is Find v: entire trip from 0 sec to tf sec

1.
A car travels down a lonely road at constant velocity 20.0
m/s. Suddenly, at t=0, the driver sees a deer in the road. After a
reaction time t = 1.5 seconds, the driver steps on the brakes and the
car then decelerates (slows down) at constant acceleration with
magnitude 4.00 m/s² before coming to rest at time tf. Below is the velocity
v vs. time t graph of the car's motion.
eose
(e)
V
R = 1.5 s
What is the time tf when the car finally comes to rest?
What is the car's displacement (in m) at t = 1.0 seconds?
What is the car's displacement (in m) at t = 4.0 seconds?
At what time t is the car's instantaneous velocity v =
5.0 m/s?
At what time t is the car 's instantaneous velocity v =
10.0 m/s?
(f)
What is the car's average velocity (in m/s) in the time
interval between tp and tf (when the car is slowing down)?
What is the total displacement (i.e. stopping distance in
meters) between t = 0 and t = tf.

Expert Solution

Step 1: First kinematic equation

Apply the first kinematic equation in the triangular part and substitute the corresponding values to calculate the final time when the car will finally come to rest.

$table row cell v equals u plus a t end cell row cell v equals u plus a left parenthesis t subscript f minus t subscript R right parenthesis end cell row cell 0 equals 20 text m/s end text plus left parenthesis negative 4 text m/s end text squared right parenthesis left parenthesis t subscript f minus 1.5 text s end text right parenthesis end cell row cell t subscript f minus 1.5 text s end text equals 5 text s end text end cell row cell t subscript f equals 6.5 text s end text end cell end table$

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