Answer all parts below, which are related to each other. The following electrochemical cell has a cell voltage of 0.033 V at 25 oC and 1.00 atmosphere pressure: Cu(s) | Cu2+(aq) (0.0010 M) || Cl-(aq) (0.10 M) | AgCl(s) | Ag(s) The following information is also known: Cu2+(aq) + 2e- <===> Cu(s) Eo = +0.339 V Ag+(aq) + e- <===> Ag(s) Eo = +0.7993 V A. Which electrode is the cathode, and why? Answer here: B. Find the [Ag+(aq)] in the right hand half-cell (compartment). Remember that AgCl(s) is very slightly soluble, so there will be some Ag+(aq) in the right side. While that is the end of this writing assignment, the answer key shows how to take things one step further and answer the more interesting chemical question of “What is the Ksp for AgCl(s)?”
Answer all parts below, which are related to each other. The following electrochemical cell has a cell voltage of 0.033 V at 25 oC and 1.00 atmosphere pressure: Cu(s) | Cu2+(aq) (0.0010 M) || Cl-(aq) (0.10 M) | AgCl(s) | Ag(s) The following information is also known: Cu2+(aq) + 2e- <===> Cu(s) Eo = +0.339 V Ag+(aq) + e- <===> Ag(s) Eo = +0.7993 V A. Which electrode is the cathode, and why? Answer here: B. Find the [Ag+(aq)] in the right hand half-cell (compartment). Remember that AgCl(s) is very slightly soluble, so there will be some Ag+(aq) in the right side. While that is the end of this writing assignment, the answer key shows how to take things one step further and answer the more interesting chemical question of “What is the Ksp for AgCl(s)?”
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Answer all parts below, which are related to each other.
The following
1.00 atmosphere pressure:
Cu(s) | Cu2+(aq) (0.0010 M) || Cl-(aq) (0.10 M) | AgCl(s) | Ag(s)
The following information is also known:
Cu2+(aq) + 2e- <===> Cu(s) Eo = +0.339 V
Ag+(aq) + e- <===> Ag(s) Eo = +0.7993 V
A. Which electrode is the cathode, and why? Answer here:
B. Find the [Ag+(aq)] in the right hand half-cell (compartment). Remember that AgCl(s) is very slightly soluble, so there will be some Ag+(aq) in the right side.
While that is the end of this writing assignment, the answer key shows how to take things one step further and answer the more interesting chemical question of “What is the Ksp for AgCl(s)?”
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