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Answer: 1.76 x 10-³ mol/L Practice Problem 2: Determine the hardness of the sample from practice problem 1 in mg of CaCO3 per liter. What is the degree of hardness? Answer: 176 mg/L, hard

Answer: 1.76 x 10-³ mol/L Practice Problem 2: Determine the hardness of the sample from practice problem 1 in mg of CaCO3 per liter. What is the degree of hardness? Answer: 176 mg/L, hard

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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st of solvent, and so forth. 2+ Practice Problem 1: The concentration of Ca²+ and Mg2+ ions in water is determined by titrating 20.00 mL of a sample with EDTA solution, 3.51 mL being required. If the EDTA solution is 1.00 x 10-2 M, what is the molarity of M²+ in the sample? Answer: 1.76 x 10-³ mol/L Practice Problem 2: Determine the hardness of the sample from practice problem 1 in mg of CaCO3 per liter. What is the degree of hardness? Answer: 176 mg/L, hard Practice Problem 3: A 1.56 M solution of Mg(OH)2 in water has a density of 1.12 g/cm³. Calculate the mass percent of Mg(OH)2 in the solution. Remember: Mass % = mass of solute / mass of solution. Answer: 8 12 %
Transcribed Image Text:st of solvent, and so forth. 2+ Practice Problem 1: The concentration of Ca²+ and Mg2+ ions in water is determined by titrating 20.00 mL of a sample with EDTA solution, 3.51 mL being required. If the EDTA solution is 1.00 x 10-2 M, what is the molarity of M²+ in the sample? Answer: 1.76 x 10-³ mol/L Practice Problem 2: Determine the hardness of the sample from practice problem 1 in mg of CaCO3 per liter. What is the degree of hardness? Answer: 176 mg/L, hard Practice Problem 3: A 1.56 M solution of Mg(OH)2 in water has a density of 1.12 g/cm³. Calculate the mass percent of Mg(OH)2 in the solution. Remember: Mass % = mass of solute / mass of solution. Answer: 8 12 %
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