Angular Velocity: Since crank AB rotates about a fixed axis. Fig. a. U-PART-5(03)-15 m/s The location of the IC for link BC is indicated in Fig. b. From the geometry of this figure, Then. ra/ic 0.5 tan 45° 0.5 m Acceleration and Angular Acceleration: Since crank AB rotates about a fixed axis, Fig. c. as-AXT₂- =(-6k) (0.3) - 5 (0.31) - 11.8-7.5j| m/s² Using this result and applying the relative acceleration equation by referring to Fig. d. cancctc ac cos 451+ ac sin 45) 0.7071ad+ 0.7071ac Equating the i and j components 0.70714--2.7 0.7071ac 0.5ac-7.5 Solving Eqs. (1) and (2), 1.5 03-3 rad/s 0-5m ܠ ܕܢ Wac Ac-3.818 m/s²-3.82 m/s aac-9.60 rad/s²) The negative sign indicates that ac acts in the opposite sense to that shown in Fig. c. doc (4) (1.84-7.5) (ack) * (03) – 3²(0.2) -2.76 (0.5am - 7.5) ac (2) 45 Ans Ans. 10.3m T asm (a) 0.5m (b) 5. Fene W-5rad/s (C) ve A W 5 rad/s PαAB 6 rad/s-

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996 answers
Angular Velocity: Since crank AB rotates about a fixed axis, Fig. a.
UR
PART 5(0.3) 1.5 m/s
The location of the IC for link BC is indicated in Fig. b. From the geometry of this
figure,
Then.
ra/ic 0.5 tan 45° 0.5 m
WIC
B
TRUC
Acceleration and Angular Acceleration: Since crank AB rotates about a fixed axis,
Fig. c.
anABXT-WARTE
= (-6k) x (0.3) - 5 (0.31)
= 11.81-7.511 m/s²
0.7071ac
Using this result and applying the relative acceleration equation by referring to Fig. d.
acaanc FC
Ca
ac cos 45'1+ ac sin 45' (1.8-7.5) (ack) (03) 3(0.30)
0.7071ad+ 0.7071acj-2.7i+ (0.5ac-7.5)
Equating the i and j components.
0.7071a-2.7
1.5
Solving Eqs (1) and (2),
0-5m
Wac
3 rad/s
140
0.5ac-7.5
Ac-3.818 m/s²= 3.82 m/s²
aac -9.60 rad/s¹
The negative sign indicates that ac acts in the opposite sense to that shown in Fig. c.
doc
ac
(1)
(2)
KAS
Ans.
Ans.
0.3m
T
enc
05m
x
ag
2013 Pediation in Unner Sarthe River NI All rights resened This nudiration is terted hi
(a)
Wo
Tele
0-5m
(b)
5.
W5rad/s
(C)
A
Who 5 rad/s
6 rad/s
Transcribed Image Text:996 answers Angular Velocity: Since crank AB rotates about a fixed axis, Fig. a. UR PART 5(0.3) 1.5 m/s The location of the IC for link BC is indicated in Fig. b. From the geometry of this figure, Then. ra/ic 0.5 tan 45° 0.5 m WIC B TRUC Acceleration and Angular Acceleration: Since crank AB rotates about a fixed axis, Fig. c. anABXT-WARTE = (-6k) x (0.3) - 5 (0.31) = 11.81-7.511 m/s² 0.7071ac Using this result and applying the relative acceleration equation by referring to Fig. d. acaanc FC Ca ac cos 45'1+ ac sin 45' (1.8-7.5) (ack) (03) 3(0.30) 0.7071ad+ 0.7071acj-2.7i+ (0.5ac-7.5) Equating the i and j components. 0.7071a-2.7 1.5 Solving Eqs (1) and (2), 0-5m Wac 3 rad/s 140 0.5ac-7.5 Ac-3.818 m/s²= 3.82 m/s² aac -9.60 rad/s¹ The negative sign indicates that ac acts in the opposite sense to that shown in Fig. c. doc ac (1) (2) KAS Ans. Ans. 0.3m T enc 05m x ag 2013 Pediation in Unner Sarthe River NI All rights resened This nudiration is terted hi (a) Wo Tele 0-5m (b) 5. W5rad/s (C) A Who 5 rad/s 6 rad/s
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