Angle Period (s) % Error 10° 1.66 7.26 20° 1.76 1.67 L 30° 1.78 0.55 40° 1.81 1.12 50° 1.82 1.68 Pendulum Length (L) = 0.8m gravity (g) 9.81 m/s^2 Small Angle Approximation Period: T=2π L = g 2pi* square root(0.8/9.81) = 1.79 s^2 60° 1.84 2.80
Angle Period (s) % Error 10° 1.66 7.26 20° 1.76 1.67 L 30° 1.78 0.55 40° 1.81 1.12 50° 1.82 1.68 Pendulum Length (L) = 0.8m gravity (g) 9.81 m/s^2 Small Angle Approximation Period: T=2π L = g 2pi* square root(0.8/9.81) = 1.79 s^2 60° 1.84 2.80
Principles of Physics: A Calculus-Based Text
5th Edition
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter1: Introduction And Vectors
Section: Chapter Questions
Problem 70P
Related questions
Question
University Physics 1 - Gravitation & Oscillation
I need help with this problem and an explanation of why its the answer described below:
A Simple Pendulum Lab (Image shown below):
What happens to the percent difference between the actual period and the small angle period as the angle increases? Explain why this matches what we expect.
![Angle
Period (s)
% Error
10°
1.66
7.26
20°
1.76
1.67
L
30°
1.78
0.55
40°
1.81
1.12
50°
1.82
1.68
Pendulum Length (L) =
0.8m
gravity (g) 9.81 m/s^2
Small Angle Approximation Period:
T=2π
L
=
g
2pi* square
root(0.8/9.81)
= 1.79 s^2
60°
1.84
2.80](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F4e135d5c-f867-4afd-9f0d-b505f4f19664%2F7e0886e9-b19a-4cc8-a7e9-b52df3f4f7aa%2Fv7s9dhc_processed.png&w=3840&q=75)
Transcribed Image Text:Angle
Period (s)
% Error
10°
1.66
7.26
20°
1.76
1.67
L
30°
1.78
0.55
40°
1.81
1.12
50°
1.82
1.68
Pendulum Length (L) =
0.8m
gravity (g) 9.81 m/s^2
Small Angle Approximation Period:
T=2π
L
=
g
2pi* square
root(0.8/9.81)
= 1.79 s^2
60°
1.84
2.80
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