A heavy block is pulled across a rough surface. In case 1, the applied force and the surface are both horizontal. In case 2, the applied force is parallel to an inclined surface up which the block is pulled. If both applied forces are identical, which of the following is true? The frictional force in case 1 is greater than the frictional force in case 2 The frictional force in case 2 is greater than the frictional force in case 1 The frictional forces are identical in magnitude in both case 1 and case 2 The frictional forces cannot be compared unless the angle of the incline is known

Name: A heavy block is pulled across a rough surface. In case 1, the applied
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Description: A heavy block is pulled across a rough surface. In case 1, the applied force and the surface are both horizontal. In case 2, the applied force is parallel to an inclined surface up which the block is pulled. If both applied forces are identical, whi

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College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Question

A heavy block is pulled across a rough surface. In case 1, the applied force and the surface are both horizontal. In case 2, the applied force is parallel to an inclined surface up which the block is pulled. If both applied forces are identical, which of the following is true?

		The frictional force in case 1 is greater than the frictional force in case 2
		The frictional force in case 2 is greater than the frictional force in case 1
		The frictional forces are identical in magnitude in both case 1 and case 2
		The frictional forces cannot be compared unless the angle of the incline is known

Expert Solution

Step 1

Expression for the friction force is

$F = μ N$

Friction force is directly proportional to the normal force.

Greater the normal force greater the friction.

For the horizontal surface (case 1) , the normal force is equal to the weight of the object

$N = W$

and for inclined surface (case 2) the normal force is equal to

$N = W \cos θ (θ - angle between the incline and horizontal surface)$

Cosine is greater when $θ = 0 °$ , this corresponds to horizontal surface.

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