NOTE:Draw in a short long bond paper.This is the format how to write in a short bond paper. I want to see in the upper right ofyour paper.> NAME OF STUDENTS> SUBJECT/SECTIONS> TEACHER> ACTIVITY NO.And after you draw your activity, please take a picture and submitEdmodo.ACTIVITY #6Example: Electron Configuration for MagnesiumMg - 1s 2s' 2p 3s?Write the complete electron configuration for each of the following elements.1. Lithium2. Охудеnп4. Carbon5. Chlorine6. Calcium7. Aluminum8. Phosphorus9. Sulfur10. Hydrogen

we are required to find the electronic configuration of the following element in its neutral state

And after you draw your activity, please take a picture and submit to Edmodo. ACTIVITY # 6 Example: Electron Configuration for Magnesium Mg - 1s° 25° 2p' 3sº Write the complete electron configuration for each of the following elements. 1. Lthum 2. Oxygen 3. Neon 4. Carbon 5. Chlorine 6. Calcium 7. Aluminum 8. Phosphorus 9. Suitur 10. Hydrogen

And after you draw your activity, please take a picture and submit to Edmodo. ACTIVITY # 6 Example: Electron Configuration for Magnesium Mg - 1s° 25° 2p' 3sº Write the complete electron configuration for each of the following elements. 1. Lthum 2. Oxygen 3. Neon 4. Carbon 5. Chlorine 6. Calcium 7. Aluminum 8. Phosphorus 9. Suitur 10. Hydrogen

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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What is the electron configuration for aluminum, AI?
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The Pauli Exclusion Principle tells us that no two electrons in an atom can have the same four quantum numbers. y For an electron in the 2s orbital shown above, enter a possible value for each quantum number. n = 1 = Give ONE example. Give ONE example. Though a given electron only has one value for possible mi, there are my values for electrons in 2s orbitals. m = m = Submit Answer Retry Entire Group 9 more group attempts remaining
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When light is shined on a thin sheet of metal, electrons are released with a kinetic energy of 6.81 x 10-21 J. If the binding energy of the metal is known to be 6.25 x 10-19 J, what is the wavelength of the light, in nm? Do not report units in your answer. Report your answer to one decimal places.
McQuarrie • Rock • Gallogly presented by Macmillan Learning Metals lose electrons under certain conditions to attain a noble gas electron configuration. How many electrons must be lost by the element Na? number of electrons: Which noble gas electron configuration is attained in this process? argon radon krypton xenon helium neon Question Source: MRG - General Chemistry | Publisher: University Science Books about us privacy policy terms of use contact us help careers
Free electrons Metal The wavelength of A is less than B or C O The intensity of B is greater than C O The intensity of A is less than B or C The frequency of B is greater than C The frequency of A is less than B or C The wavelength B is greater than C Emitted free electrons Three different lasers (A, B and C), each with a different wavelength, is focused on the same alkali metal. Laser A light has no effect on the metal. Light from laser B and C both cause electrons to be released from the metal, but the light from laser B releases more electrons. Which of the following statements must be true?
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Alpha emissions from Po-210 are used in paper manufacturing to reduce static electricity. This is possible since alpha particles can easily knock off electrons catalyze chemical reactions, which involve valence electrons are positively charged so they attract electrons create enough heat to catalyze chemical reactions that use up electrons