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and 1 atm (Q is for complete reaction): C(graphite) + H2(g) - CH4(g) 1 Q = -285.84 kl/mol H-

and 1 atm (Q is for complete reaction): C(graphite) + H2(g) - CH4(g) 1 Q = -285.84 kl/mol H-

Introduction to Chemical Engineering Thermodynamics
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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Given the following experimental results of the hydrogenation reaction of graphite at 25°C and 1 atm (Q is for complete reaction): C(graphite) + H2(g) → CH4(g) Q = -285.84 kJ/mol H2 Q = -393.51 kJ/mol C Q = -890.36 kJ/mol CH, H2(g) +502(g) → H20(1) C(graphite) + 02(g) → CO2(g) CHĄ(g) + 20,(g) → CO2(g) + 2H,0(1) %3D (a) Calculate the standard heat of reaction to form CH4.
Transcribed Image Text:Given the following experimental results of the hydrogenation reaction of graphite at 25°C and 1 atm (Q is for complete reaction): C(graphite) + H2(g) → CH4(g) Q = -285.84 kJ/mol H2 Q = -393.51 kJ/mol C Q = -890.36 kJ/mol CH, H2(g) +502(g) → H20(1) C(graphite) + 02(g) → CO2(g) CHĄ(g) + 20,(g) → CO2(g) + 2H,0(1) %3D (a) Calculate the standard heat of reaction to form CH4.
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