2. The catalytic oxidation of ammonia may proceed by two reactions 4 NH3 + 5 0₂4 NO + 6H₂O 4 NH3 + 3 0₂2 N₂ + 6H₂O A reactor is charged with the following amounts. Initial Charge nNH, = 3.58 mol nNO= 2.28 mol "Hạo=9.25 mol no₂ nN₂ = 6.12 mol = 1.87 mol (1) (2) Calculate the amounts (moles) of each species in the reactor after the reactions proceed with

Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
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2. The catalytic oxidation of ammonia may proceed by two reactions
4 NH3 + 5 0₂4 NO + 6H₂O
4 NH3 + 3 0₂2 N₂ + 6H₂O
A reactor is charged with the following amounts.
Initial Charge
nNH, = 3.58 mol
nNO= 2.28 mol
nH,o=9.25 mol
no₂ = 6.12 mol
nN₂
= 1.87 mol
(1)
(2)
Calculate the amounts (moles) of each species in the reactor after the reactions proceed with
₁ = 0.55 and ₂ = -0.38.
Transcribed Image Text:2. The catalytic oxidation of ammonia may proceed by two reactions 4 NH3 + 5 0₂4 NO + 6H₂O 4 NH3 + 3 0₂2 N₂ + 6H₂O A reactor is charged with the following amounts. Initial Charge nNH, = 3.58 mol nNO= 2.28 mol nH,o=9.25 mol no₂ = 6.12 mol nN₂ = 1.87 mol (1) (2) Calculate the amounts (moles) of each species in the reactor after the reactions proceed with ₁ = 0.55 and ₂ = -0.38.
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