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Example 2: For the reaction bellow: CnH(2n+2) + a(02 +3.76 N₂)→nCO₂ + (n+1)H₂O + 3.76a N₂ If the heat of combustion writing as: Qc = 618.49 n + 187.83 And the mole fraction of CO2 in products is Xco₂ (KJ/mole of fuel) 25 227 = 9 find: 1. Type of fuel. 2. Heat of combustion 3. If n=4, find the mole fractions of CO2, H₂O and N₂ Solution:

Example 2: For the reaction bellow: CnH(2n+2) + a(02 +3.76 N₂)→nCO₂ + (n+1)H₂O + 3.76a N₂ If the heat of combustion writing as: Qc = 618.49 n + 187.83 And the mole fraction of CO2 in products is Xco₂ (KJ/mole of fuel) 25 227 = 9 find: 1. Type of fuel. 2. Heat of combustion 3. If n=4, find the mole fractions of CO2, H₂O and N₂ Solution:

Introduction to Chemical Engineering Thermodynamics
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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Example 2: For the reaction bellow: CnH(2n+2) + a(0₂ +3.76 N₂) - nCO₂ + (n +1) H₂0 +3.76a N₂ - If the heat of combustion writing as: Qc = 618.49 n + 187.83 (KJ/mole of fuel) 25 227 And the mole fraction of CO₂ in products is Xco₂ 1. Type of fuel. 2. Heat of combustion - find: 3. If n=4, find the mole fractions of CO2, H₂O and N₂ Solution:
Transcribed Image Text:Example 2: For the reaction bellow: CnH(2n+2) + a(0₂ +3.76 N₂) - nCO₂ + (n +1) H₂0 +3.76a N₂ - If the heat of combustion writing as: Qc = 618.49 n + 187.83 (KJ/mole of fuel) 25 227 And the mole fraction of CO₂ in products is Xco₂ 1. Type of fuel. 2. Heat of combustion - find: 3. If n=4, find the mole fractions of CO2, H₂O and N₂ Solution:
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