Analyzing the Data 1. When the uncorrected volume is doubled from 5.0 mL to 10.0 mL, how does the pressure change, according to your data? a. Calculate the pressure ratio using your corresponding pressure data from these two volumes, Vinitial = 5.0 mL and Vfinal = 10.0 mL. Set up the pressure ratio for Pfinal and calculate its value. the corresponding pressures as Pinitial 187.79 97.95 b. Answer in words, such as "pressure is reduced by half," or "pressure is reduced to ½ of the original pressure," as related to the numerical answer obtained in part a). Use similar words/phrases to answer questions 2 and 3.

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Chapter1: Chemical Foundations
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Name Kayla Trujillo
1. When the uncorrected volume is doubled from 5.0 mL to 10.0 mL, how does the
pressure change, according to your data?
2
Analyzing the Data
a. Calculate the pressure ratio using your corresponding pressure data from these
two volumes, Vinitial = 5.0 mL and Vfinal = 10.0 mL. Set up the pressure ratio for
Pfinal and calculate its value.
the corresponding pressures as
Pinitial
187.79
97.95
b. Answer in words, such as "pressure is reduced by half," or "pressure is reduced
to ½ of the original pressure," as related to the numerical answer obtained in
part a). Use similar words/phrases to answer questions 2 and 3.
When the uncorrected volume is halved from 20.0 mL to 10.0 mL, how does the
Transcribed Image Text:Name Kayla Trujillo 1. When the uncorrected volume is doubled from 5.0 mL to 10.0 mL, how does the pressure change, according to your data? 2 Analyzing the Data a. Calculate the pressure ratio using your corresponding pressure data from these two volumes, Vinitial = 5.0 mL and Vfinal = 10.0 mL. Set up the pressure ratio for Pfinal and calculate its value. the corresponding pressures as Pinitial 187.79 97.95 b. Answer in words, such as "pressure is reduced by half," or "pressure is reduced to ½ of the original pressure," as related to the numerical answer obtained in part a). Use similar words/phrases to answer questions 2 and 3. When the uncorrected volume is halved from 20.0 mL to 10.0 mL, how does the
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