Analyze the following pair of compounds. Which of the terms explains the relationship between the two compounds OH CH₂OH OH anomers OH a-D-galactose enantiomers epimers diastereomers ОН OH CH OH ОН он ОН a-L-galactose
Analyze the following pair of compounds. Which of the terms explains the relationship between the two compounds OH CH₂OH OH anomers OH a-D-galactose enantiomers epimers diastereomers ОН OH CH OH ОН он ОН a-L-galactose
Biochemistry
9th Edition
ISBN:9781319114671
Author:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.
Publisher:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.
Chapter1: Biochemistry: An Evolving Science
Section: Chapter Questions
Problem 1P
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6.
The chemical structure on the left depicts α-D-galactose. It is a six-membered ring with the hydroxyl (OH) groups positioned as follows: the first carbon has an OH pointing downward, and the fourth carbon has an OH pointing upward. The CH₂OH group is on the fifth carbon pointing upward.
The chemical structure on the right is α-L-galactose. The hydroxyl (OH) groups are arranged differently: the first carbon has an OH group pointing downward, similar to the α-D-galactose, but the spatial orientation of the entire molecule is mirrored compared to its D counterpart. The CH₂OH group on the fifth carbon points downward.
**Options**:
- [ ] anomers
- [ ] enantiomers
- [ ] epimers
- [ ] diastereomers
These terms are used to describe the stereochemical relationships between two molecules:
- **Anomers**: Isomers that differ specifically at the new chiral center formed on the carbon (known as the anomeric carbon) resulting from cyclization.
- **Enantiomers**: Stereoisomers that are non-superimposable mirror images of each other.
- **Epimers**: Stereoisomers that differ in configuration at exactly one chiral center.
- **Diastereomers**: Stereoisomers that are not mirror images and differ at two or more chiral centers.
Note: α-D-galactose and α-L-galactose are enantiomers, as they are mirror images of each other but not superimposable.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F81e33e53-6cee-49a0-88a3-901e9c69b620%2Fa0f575cc-481e-49a3-83f1-92ef48c96673%2F3dgrlcu_processed.png&w=3840&q=75)
Transcribed Image Text:**Analyze the following pair of compounds. Which of the terms explains the relationship between the two compounds?**
The chemical structure on the left depicts α-D-galactose. It is a six-membered ring with the hydroxyl (OH) groups positioned as follows: the first carbon has an OH pointing downward, and the fourth carbon has an OH pointing upward. The CH₂OH group is on the fifth carbon pointing upward.
The chemical structure on the right is α-L-galactose. The hydroxyl (OH) groups are arranged differently: the first carbon has an OH group pointing downward, similar to the α-D-galactose, but the spatial orientation of the entire molecule is mirrored compared to its D counterpart. The CH₂OH group on the fifth carbon points downward.
**Options**:
- [ ] anomers
- [ ] enantiomers
- [ ] epimers
- [ ] diastereomers
These terms are used to describe the stereochemical relationships between two molecules:
- **Anomers**: Isomers that differ specifically at the new chiral center formed on the carbon (known as the anomeric carbon) resulting from cyclization.
- **Enantiomers**: Stereoisomers that are non-superimposable mirror images of each other.
- **Epimers**: Stereoisomers that differ in configuration at exactly one chiral center.
- **Diastereomers**: Stereoisomers that are not mirror images and differ at two or more chiral centers.
Note: α-D-galactose and α-L-galactose are enantiomers, as they are mirror images of each other but not superimposable.
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