Analyze the following code: public class Test { public static void main (String [] args) { int i = 0; while (i ++ < 10); System.out.printin(i + 4); O The program compiles despite the semicolon (;) on the for loop line, and displays 15. The program has a compile error because of the semicolon (;) on the while loop line. The program compiles despite the semicolon (:) on the while loop line, and displays 4.
Analyze the following code: public class Test { public static void main (String [] args) { int i = 0; while (i ++ < 10); System.out.printin(i + 4); O The program compiles despite the semicolon (;) on the for loop line, and displays 15. The program has a compile error because of the semicolon (;) on the while loop line. The program compiles despite the semicolon (:) on the while loop line, and displays 4.
Chapter8: Advanced Method Concepts
Section: Chapter Questions
Problem 8RQ
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![QUESTION 4
Analyze the following code:
public class Test {
public static void main (String [] args) {
int i = 0;
while (i ++ < 10);
System.out.println(i + 4);
The program compiles despite the semicolon () on the for loop line, and displays 15.
The program has a compile error because of the semicolon (;) on the while loop line.
The program compiles despite the semicolon (:) on the while loop line, and displays 4.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F438569bc-ed7d-4d59-a45a-430701614f97%2F2e09b691-2226-4399-b628-98f14ed27d05%2F7ydl0av_processed.jpeg&w=3840&q=75)
Transcribed Image Text:QUESTION 4
Analyze the following code:
public class Test {
public static void main (String [] args) {
int i = 0;
while (i ++ < 10);
System.out.println(i + 4);
The program compiles despite the semicolon () on the for loop line, and displays 15.
The program has a compile error because of the semicolon (;) on the while loop line.
The program compiles despite the semicolon (:) on the while loop line, and displays 4.
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