Analyze the following code: public class Test { public static void main (String [] args) { int i = 0; while (i ++ < 10); System.out.printin(i + 4); O The program compiles despite the semicolon (;) on the for loop line, and displays 15. The program has a compile error because of the semicolon (;) on the while loop line. The program compiles despite the semicolon (:) on the while loop line, and displays 4.

Microsoft Visual C#
7th Edition
ISBN:9781337102100
Author:Joyce, Farrell.
Publisher:Joyce, Farrell.
Chapter8: Advanced Method Concepts
Section: Chapter Questions
Problem 8RQ
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QUESTION 4
Analyze the following code:
public class Test {
public static void main (String [] args) {
int i = 0;
while (i ++ < 10);
System.out.println(i + 4);
The program compiles despite the semicolon () on the for loop line, and displays 15.
The program has a compile error because of the semicolon (;) on the while loop line.
The program compiles despite the semicolon (:) on the while loop line, and displays 4.
Transcribed Image Text:QUESTION 4 Analyze the following code: public class Test { public static void main (String [] args) { int i = 0; while (i ++ < 10); System.out.println(i + 4); The program compiles despite the semicolon () on the for loop line, and displays 15. The program has a compile error because of the semicolon (;) on the while loop line. The program compiles despite the semicolon (:) on the while loop line, and displays 4.
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