An unknown compound, I, has the formula C3H;NO2. Elucidate the structure of I by scrutinizing its IR, 'H NMR and 13C NMR spectra, shown below. 100 50 4000 3000 2000 1000 Wavenumbers (cm') 4.5 4.0 3.5 3.0 2.5 2.0 1.5 1.0 ppm ihe 77.5 77.0 ppm 95 90 85 80 75 70 65 60 55 50 45 40 35 30 25 20 15 10 ppm is >-1134 --1227 -1381 --1435 -2885 2947 2978 %Transmittance

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An unknown compound, I, has the formula C3H¬NO2. Elucidate the structure of I by scrutinizing
its IR, 'H NMR and 13C NMR spectra, shown below.
100
50
4000
3000
2000
1000
Wavenumbers (cm)
4.5
4.0
3.5
3.0
2.5
2.0
1.5
1.0
ppm
ihe
77.5
77.0
ppm
95
90 85 80
75
70
65
60
55
50 45
40 35
30 25
15
10
ppm
>-1134
--1227
20
--1381
>-1435
-1558|
z~2885
-2947
2978
%Transmittance
Transcribed Image Text:An unknown compound, I, has the formula C3H¬NO2. Elucidate the structure of I by scrutinizing its IR, 'H NMR and 13C NMR spectra, shown below. 100 50 4000 3000 2000 1000 Wavenumbers (cm) 4.5 4.0 3.5 3.0 2.5 2.0 1.5 1.0 ppm ihe 77.5 77.0 ppm 95 90 85 80 75 70 65 60 55 50 45 40 35 30 25 15 10 ppm >-1134 --1227 20 --1381 >-1435 -1558| z~2885 -2947 2978 %Transmittance
Expert Solution
Double bond equivalent calculation and analysis of IR

C3H7NO2 has double bond equivalent = 1 [for CaHbNcOcompound double bond equivalent = a+1-((b-c)/2) ]

this 1 double bond equivalent means this compound has one unsaturation or ring.

now, I.R. data shows absorption around 1558 means N=O bond stretching so, this satisfies 1 unsaturation. Also from IR that absorption around 2900 tells sp3C-H stretching. That means in this compound sp3 carbon present which contains H atom/s.

from this IR datas we can assure that in this compound NO2 group is present.

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