An unequal leg angle-iron is loaded as shown inFig. 9.12. Determine the stress at point B.Solution.R₁ = 4 kNMc = Mmax4x2=8 kN.mA₁ = 15 cm², A₂= 20-25 cm2, A = 35-25 cm²15 x 5+20-25 × 0.75X2.56 cm35-2515 x 0.75 +20-25 × 8-25y= 5.06 cm35-25P=4kN4kNc↓Ak2m+la15cm(1(2)*k1.5cm182m(a)Y10cmI45°(b)Fig. 9.12Toto45°-0PB1.5cm➤ X2mB

Stress at B , σ=MyI As solved in the above image where M= 8 KNM…

An unequal leg angle-iron is loaded as shown in Fig. 9.12. Determine the stress at point B. Solution. RA 4 kN Mc = Mmax = 4 x 2 = 8 kN.m A₁ 1 15 cm², A₂= 20-25 cm2, A = 35-25 cm² 15 x 5+20-25 × 0.75 2.56 cm - 35-25 15 x 0.75 +20-25 × 8.25 = 5.06 cm 35-25 P=4kN 4kN A y = 2m la ✈ 15cm - pº Ik 1.5cm 2m (a) Y 10cm I 45° (b) Fig. 9.12 0 D 45°-0 P BV 1.5cm x 2m B 000

An unequal leg angle-iron is loaded as shown in Fig. 9.12. Determine the stress at point B. Solution. RA 4 kN Mc = Mmax = 4 x 2 = 8 kN.m A₁ 1 15 cm², A₂= 20-25 cm2, A = 35-25 cm² 15 x 5+20-25 × 0.75 2.56 cm - 35-25 15 x 0.75 +20-25 × 8.25 = 5.06 cm 35-25 P=4kN 4kN A y = 2m la ✈ 15cm - pº Ik 1.5cm 2m (a) Y 10cm I 45° (b) Fig. 9.12 0 D 45°-0 P BV 1.5cm x 2m B 000

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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