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o Given: A stepped shaft with the following properties Copper: A = 2 in² E = 16 × 106 psi Steel: A = 1 in² psi E = 30 × 106 copper 12" steel 12" P steel 12" copper 6" P HA o Find: P such that the deformation, A is 0.1 in at the end of the bar.

o Given: A stepped shaft with the following properties Copper: A = 2 in² E = 16 × 106 psi Steel: A = 1 in² psi E = 30 × 106 copper 12" steel 12" P steel 12" copper 6" P HA o Find: P such that the deformation, A is 0.1 in at the end of the bar.

Structural Analysis
Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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o Given: A stepped shaft with the following properties Copper: A = 2 in² E = 16 × 106 psi Steel: A = 1 in² E = 30 × 106 psi copper 12" steel 12" P steel 12" copper 6" → P HA o Find: P such that the deformation, A is 0.1 in at the end of the bar.
Transcribed Image Text:o Given: A stepped shaft with the following properties Copper: A = 2 in² E = 16 × 106 psi Steel: A = 1 in² E = 30 × 106 psi copper 12" steel 12" P steel 12" copper 6" → P HA o Find: P such that the deformation, A is 0.1 in at the end of the bar.
Expert Solution
Step 1: State of given data

Given 

Copper and steel

Area and Elasticity modulus of copper is 2 in2 and 16×106 psi

Area and Elasticity modulus of steel is 1 in2  and 16×106 psi

Total deflection 0.1 in

To find out 

Load P

steps

Step by step

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