An saw blade starts from 5 rad/s and accelerates at 3 rad/s2 and covers 252 rad. Determine the time it takes

College Physics
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ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
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An saw blade starts from 5 rad/s and accelerates at 3 rad/s2 and covers 252 rad. Determine the time it takes.

Note, the formula will still have  t and t2 so it's a quadratic equation, and we can use the quadratic formula. POSTED IN IMAGES

 

Steps:

  • Simplify as much as possible and arrange in descending order - that is, get everything on one side of the equation with a zero on the other side and rearrange the terms so that t2 comes first, t comes second and the constant term is last
  • the quad formula has a, b, and c which are the coefficients of the t2 term, the t term and the constant term including the positive or negative signs
  • example:
    • If 4 = 2 t + 1/2 (8) t2
    • Simplify 1/2 (8) = 4, subtract 4 from both sides and rearrange the terms to get   0 = 4t2 + 2t - 4
    • now a = 4, b = 2, c = -4
    • plug these into the quadratic formula and get the two solutions, one when we use the + and the other when we use the - in the formula, just before the square root. Usually we want the positive solution
      • (-2+√(22-4(4)(-4))).(2*4) = 0.78
      • (-2-√(22-4(4)(-4))).(2*4) = -1.3
The image displays the quadratic formula for finding the variable \( t \) in a quadratic equation:

\[ 
t = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{2a} 
\]

This formula is used to find the solutions to the quadratic equation \( at^2 + bt + c = 0 \). Here, \( a \), \( b \), and \( c \) are coefficients of the equation, and the symbol \( \pm \) indicates that there are generally two solutions: one involving addition and the other involving subtraction. The expression under the square root, \( b^2 - 4ac \), is known as the discriminant.
Transcribed Image Text:The image displays the quadratic formula for finding the variable \( t \) in a quadratic equation: \[ t = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{2a} \] This formula is used to find the solutions to the quadratic equation \( at^2 + bt + c = 0 \). Here, \( a \), \( b \), and \( c \) are coefficients of the equation, and the symbol \( \pm \) indicates that there are generally two solutions: one involving addition and the other involving subtraction. The expression under the square root, \( b^2 - 4ac \), is known as the discriminant.
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