This is the answer to one of my practice problems, however I don't understand how the angular acceleration is simplified for A, B and C. How does rFsin90/(2M)(2L) equal 3F/ML and etc. for the other ones? And then after you simplify all the angular accelerations, how do you know which one is smallest to greatest? How do you tell that C is greater than B?
This is the answer to one of my practice problems, however I don't understand how the angular acceleration is simplified for A, B and C. How does rFsin90/(2M)(2L) equal 3F/ML and etc. for the other ones? And then after you simplify all the angular accelerations, how do you know which one is smallest to greatest? How do you tell that C is greater than B?
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This is the answer to one of my practice problems, however I don't understand how the
Transcribed Image Text:B:
To the right are top views of three rods that vary
in mass M and length L. The rods are fixed at
the circular point at one end and a force is ap-
plied to the other end. Note that the moment
of inertia of a rod about its end is I = mr² where m is the mass and r is the length.
4F
Rank the situations based on the magnitude of the angular acceleration of the rods.
î = Id So
But z=pF₁:
The
Largest
A = C > B
Explain your reasoning and show at least one example of your calculation.
x=
C: α =
A: α = 3 (4F) sin 90
(2M)(2L)
rf sin Ⓒ
mp²
a=
3 (F) Sin 90
ML
=
α = 3(4F) sin 30 3F
(M) (4L)
2ML
2M
A
3F
ML
3F
7/4
I
2L
3F sine
=r Fsin ← Angle between
rod and force
mr
ML
OM 4L
Smallest
30`-
z
2
} mp²
4F
с
OM L
OF
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