An overhang beam carries a concentrated load, P and a uniform load, w = 15 kN/m. If the point of contra-flexure (where bending moment is zero) is located 0.5 m from support B, determine the absolute value of P (in kN). P (kN) w (KN/m) SM

An overhang beam carries a concentrated load, P and a uniform load, w = 15 kN/m. If the point of contra-flexure (where bending moment is zero) is located 0.5 m from support B, determine the absolute value of P (in kN). P (kN) w (KN/m) SM

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

A rectangular beam 400 mm deep and 300 mm wide is simply supported over a span of 4 m. If the bending stress in the beam is not to exceed 120 MPa then the value of uniformly distributed load that the beam can carry is. kN/m. m
1. Solve and show solution W1=115 p1=30 p2=35 p3=40 p4=50
The steel framework is used to support the 100 mm plain light weight concrete slab that carries a live loading of 2.4 kN/m2. Determine the loading in kN/m that acts in member CD. set b = 3.6 m and a = 1.2 m.
A simply supported beam AB = 10 m has a hollow rectangular cross-section with 10 cm as width, 23 cm as depth and inner thickness as 2 cm is subjected to a point load of 8 N & 9 N acting at C and D respectively and a uniformly distributed load (UDL) of 8 N/m starts from mid-span and ends at the right support of the beam. Determine the maximum bending stress and the bending stress at 2 cm from the top. Take AC = 1 m & CD = 1 m. iv) Maximum Bending Moment (Please write the Maximum bending moment valve in "Nm") = v) Moment of Inertia, I = vi) Maximum bending stress = vii) Bending stress at 2 cm from the top =
these are the follow up questions a) Determine the horizontal reaction at ‘C’ in kN. b) Determine the vertical reaction at ‘C’ in kN.
If M = 5.41 and w = 26.4, Determine the Shear Force at point B of the Beam shown. w in kN/m Min kN.m C 3 m A B 4 m
A 3-m span cantilever beam carries a uniformly distributed load of 36 KN/m over its entire length. The beam has a rectangular cross-section with height h twice its width b. The allowable stresses are: flexure stress, fb ≤ 30 MPa and shearing stress, fv ≤ 3 MPa. Determine: The maximum shear force along the length of the beam (in KN).
A 4-m span wooden beam with rectangular section simply supports a uniform distributed loading of w=15.85 in KN/m. One support (roller) is located 1-m from the left end and the other support (hinged) is located at the right end of the span. The allowable bending stress is 9 MPa and the allowable shearing stress is 0.60 MPa. Neglect the beam weight and assume the beam to have a depth to width ratio of 1.50. What is the width of the beam so that it will not exceed the allowable bending stress?
RCC.
Figure 4 below shows a 10 m length of beam with a pinned support at A and rollersupport at C. The beam carries a uniformly distributed load (UDL) of 5 kN/m acrosssection B to C and a concentrated load of 25 kN at D.a. Show the Free Body Diagram (FBD) of the beam then determine the reactionforce.b. Calculate the shear force, V. Draw Shear Force Diagram (SFD).c. Calculate the bending moment, M. Draw the Bending Moment Diagram (BMD).
A 12 m beam is simply supported at the left end and is fixed at the right end. It is subjected to a uniform distributed load of 12 kN/m. Calculate the maximum shear force (kN) in the beam. Assume that the flexural rigidity of the beam is constant all throughout.