An organic compound has a percent composition, 89.84 %C, 10.17 %H. This compound has anapproximate boiling point of 152 °C at 757 mmHg. The IR spectrum of the neat thin film is shown below.Propose a structure of this compound and show your rational for full credit.LD3084G2207111664212017710284430645319428414E053121384922813028371868614523111508690579300268180084138462114486BOTT8162296171604621364 57699429273515838419231082555Б4209046149420110067479B4D40003000200015001000500TRANSHITTANCEIXI

Given: Percent composition of carbon= 89.84% Percent composition of hydrogen=10.17% Boiling point of…

Answered: An organic compound has a percent…

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Chemistry This IR spectrum demonstrates constitutional isomers containing the same molecular formula of C8H8O2. This spectra could correspond to methyl benzoate or the other 2 possible constitutional isomers. Please identify the correct structure for this IR spectrum and interpret the spectrum according to the medium-strong peaks displayed. Please be organzied, write neatly, or type up the answer. Thank you.
The two NMR spectra below are from two isomers with the formula C10H12O. The IR spectra show strong bands near 1715 cm and in the range 1600 to 1450 cm. Draw their structures and explain reasoning.
A student was trying to determine the identity of an unknown compound. The melting point of the compound was 117-118oC. The student narrowed the possible compound down to the following: Compound Melting Point Range acetanilide 113-115oC fluorene 114-116oC mandelic acid 120-122oC A second student, doing the same experiment as above, found that their melting point was 100-108oC. What is wrong with the student’s melting point? Propose two reasons why the melting point could be incorrect. View keyboard shortcuts
Identify the probable structure from the following IR spectrum.
The IR and mass spectra of a compound are shown below. Suggest a possible structure for the compound, explaining how you reach your decision.
UV: max 235 (ε 12,000) and max 314 (ε 120) EIMS: m/z 39 (31%), 41 (33%), 55 (37%), 69 (26%), 98 (100%), 99 (7%), 100 (0.2%) IR: Imm IR spectrum in CCl4 solvent 2950 cm-¹ 2000 4) RC=N 5) 0-H BAYEHUNIERI - R 1630 cm-¹ 1710 cm-¹ $10 4a) Which of the following heteroatoms that are definitely NOT present based on the EIMS data? (Circle all that apply). Br Cl FSI 0 4 continued) Please refer to data on preceding page. 4b) From the EIMS data what is the best estimate of the number of carbon atoms in this molecule? 4c) From the UV data, conjugated л-bonds are: definitely present definitely absent 4d) From the IR spectrum alone, which of the following functional groups can be definitely ruled OUT? Circle those that are ruled out and briefly explain why. 1) C=0 2) RC=CR 3) C=C cannot tell
Chemistry Name the compound using mass spec, NMR, and IR.
Use the 1H NMR and IR data to determine the structure of attachedcompound.
IR Spec, Mass Spec, and CNMR structure analysis.
Analyze the scpectra below, assign/label significant peaks and draw the isomers (correct structure of the formula C5H9N
The UV spectrum of acetone shows absorption maxima at 166, 189, and 279 nm. What type of transition is responsible for each of these bands?
Practice q # 7 7. The IR and the ¹H NMR spectra of an unknown with a molecular formula of C8H₁5NO2 are shown below. The questions that follow will guide you in the determination of its structure. 25 26 27 28 29 3 100 90 80 70 60 50 40 30 20 10 0 4000 7 3800 3600 3400 3200 3000 2800 2600 2400 2200 F 3.5 6 4.5 D 5 5 2000 5.5 1800 MICRONS 1600 WAVENUMBERS D 4 7 1400 8 1200 C 3 10 1000 B a. Determine the degree of unsaturation. Show your calculation. 11 A 2 NICOLET 20SX FT-IR 12 13 14 15 16 17 18 19 21 22 +0.0 800 1 600 b. Analyze three significant bands in the IR spectra and conclude on the existing functions. 05 02 +0.3 0.4 0.5 0.6 +0.7 0.8 0.9 1.0 2.0 450 0

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