An oil drop of mass 8×10-9 kg is suspended in a down electric field of magnitude 8.7x105 N/C. Consider the acceleration of gravity g = 10 m/s². In terms of the charge of the electron 1.6 × 1019) C, the net charge on the oil drop is (q= (Note: en means 10" in the answer) 9.8e5 electron .a O 2.9e5 electron.b O 7.5e5 electron.c O 1.5e5 electron .d O 5.7e5 electron.e O Clear my choice
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