0.21 m 9planet = = T2 (0.92 s)² 2 9.8 m/s² Constants In this example we will use pendulum motion to actually measure the acceleration of gravity on a different planet. An astronaut on the surface of Mars measures the frequency of oscillation of a simple pendulum consisting of a ball on the end of a string. He finds that the pendulum oscillates with a period of 1.5 s. But the acceleration due to gravity on Mars is less than that on earth, 9Mars = 0.389 earth. Later, during a journey to another planet, the astronaut finds that his simple pendulum oscillates with a period of 0.92 s. What planet is he now on? He is on planet earth! REFLECT In principle, an astronaut can use this method to measure the acceleration due to gravity of any planet or satellite while traveling around the solar system. Part A Practice Problem: The acceleration due to gravity near the surface of a distant planet is about 3.6 m/s2. If the astronaut arrives there and swings the same pendulum bob, what will be the period of the pendulum? Express your answer in seconds to two significant figures. Η ΑΣΦ Submit Request Answer ? S
0.21 m 9planet = = T2 (0.92 s)² 2 9.8 m/s² Constants In this example we will use pendulum motion to actually measure the acceleration of gravity on a different planet. An astronaut on the surface of Mars measures the frequency of oscillation of a simple pendulum consisting of a ball on the end of a string. He finds that the pendulum oscillates with a period of 1.5 s. But the acceleration due to gravity on Mars is less than that on earth, 9Mars = 0.389 earth. Later, during a journey to another planet, the astronaut finds that his simple pendulum oscillates with a period of 0.92 s. What planet is he now on? He is on planet earth! REFLECT In principle, an astronaut can use this method to measure the acceleration due to gravity of any planet or satellite while traveling around the solar system. Part A Practice Problem: The acceleration due to gravity near the surface of a distant planet is about 3.6 m/s2. If the astronaut arrives there and swings the same pendulum bob, what will be the period of the pendulum? Express your answer in seconds to two significant figures. Η ΑΣΦ Submit Request Answer ? S
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Transcribed Image Text:0.21 m
9planet
=
=
T2
(0.92 s)²
2
9.8 m/s²
Constants
In this example we will use pendulum motion to
actually measure the acceleration of gravity on a
different planet. An astronaut on the surface of
Mars measures the frequency of oscillation of a
simple pendulum consisting of a ball on the end of
a string. He finds that the pendulum oscillates with
a period of 1.5 s. But the acceleration due to gravity
on Mars is less than that on earth,
9Mars = 0.389 earth. Later, during a journey to
another planet, the astronaut finds that his simple
pendulum oscillates with a period of 0.92 s. What
planet is he now on?
He is on planet earth!
REFLECT In principle, an astronaut can use this method to measure the acceleration due to gravity of
any planet or satellite while traveling around the solar system.
Part A Practice Problem:
The acceleration due to gravity near the surface of a distant planet is about 3.6 m/s2. If the
astronaut arrives there and swings the same pendulum bob, what will be the period of the
pendulum?
Express your answer in seconds to two significant figures.
Η ΑΣΦ
Submit Request Answer
?
S
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