An oceanographer wants to test, on the basis of the mean of a random sample of size n = 35 and at the 0.05 level of significance, whether the average depth of the ocean in a certain area is 72.4 fathoms, as has been recorded. What will she decide if she gets x =73. 2 fathoms, and she can assume from information gathered in similar studies that ơ = 2. 1 fathoms? Instructions: Assume a two-tailed test, in addressing the problem obtain the value of the test statistic and its corresponding p – value up to four decimal places. 2 3 2.2537;B р — value — 0. 0242 О2%3D1.2511; р- value 3 0. 0512 z 3 2. 2537; р — value 3 0.0121 23D 2. 5543;Bр— value = 0. 0523 |

MATLAB: An Introduction with Applications
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Author:Amos Gilat
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Chapter1: Starting With Matlab
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An oceanographer wants to test, on the basis of the mean of a random sample of
size n = 35 and at the 0.05 level of significance, whether the average depth of
the ocean in a certain area is 72.4 fathoms, as has been recorded. What will she
decide if she gets x = 73. 2 fathoms, and she can assume from information
gathered in similar studies that ơ = 2.1 fathoms?
Instructions: Assume a two-tailed test, in addressing the problem obtain the value of
the test statistic and its corresponding p – value up to four decimal places.
Ох3 2. 2537; р- value — 0.0242
z = 1. 2511; p – value = 0.0512
О23 2.2537; р- value 3 0. 0121
2%3D 2. 5543; р—
value = 0. 0523
Transcribed Image Text:An oceanographer wants to test, on the basis of the mean of a random sample of size n = 35 and at the 0.05 level of significance, whether the average depth of the ocean in a certain area is 72.4 fathoms, as has been recorded. What will she decide if she gets x = 73. 2 fathoms, and she can assume from information gathered in similar studies that ơ = 2.1 fathoms? Instructions: Assume a two-tailed test, in addressing the problem obtain the value of the test statistic and its corresponding p – value up to four decimal places. Ох3 2. 2537; р- value — 0.0242 z = 1. 2511; p – value = 0.0512 О23 2.2537; р- value 3 0. 0121 2%3D 2. 5543; р— value = 0. 0523
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