1. (Use Lynch's Formula) How many sample units must be obtained from 6,500 CSTCians if a 5% margin of error is used?

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NOTE: PLEASE FOLLOW LYNCH’s FORMULA IN THE PHOTO ATTACHED.
Å
1. (Use Lynch's Formula) How many sample units must be obtained
from 6,500 CSTCians if a 5% margin of error is used?
Solution
Interpretation
Transcribed Image Text:Å 1. (Use Lynch's Formula) How many sample units must be obtained from 6,500 CSTCians if a 5% margin of error is used? Solution Interpretation
Lynch's Formula
Where:
n =
n = sample size
N = population size
z = normal variable for reliability level of 95% (usually 1.96)
P = largest possible proportion (usually 0.50)
d = sampling error (usually 0.05)
Example: Compute a sufficient sample size of a target population consisting of 1,524
junior high school students using Lynch's Formula.
Solution:
NZ²-P(1-P)
Nd²+[Z² .P(1-P)]
=
=
=
n =
NZ². P(1-P)
.
Nd² + [Z² · P(1 − P)]
1,524 (1.96)²-(0.50) (1-0.50)
1,524 (0.05)² +[(1.96) ² (0.50)(1-0.50)]
1,463.6496
3.81 +0.9604
1,524(3.8416) (0.50) (0.50)
1,524 (0.0025)+ [(3.8416) (0.50) (0.50)]
5854.5984-0.25
3.81 +[(3.8416) (0.25)]
1,463.6496
4.7704
= 306.8190508
≈ 307
Transcribed Image Text:Lynch's Formula Where: n = n = sample size N = population size z = normal variable for reliability level of 95% (usually 1.96) P = largest possible proportion (usually 0.50) d = sampling error (usually 0.05) Example: Compute a sufficient sample size of a target population consisting of 1,524 junior high school students using Lynch's Formula. Solution: NZ²-P(1-P) Nd²+[Z² .P(1-P)] = = = n = NZ². P(1-P) . Nd² + [Z² · P(1 − P)] 1,524 (1.96)²-(0.50) (1-0.50) 1,524 (0.05)² +[(1.96) ² (0.50)(1-0.50)] 1,463.6496 3.81 +0.9604 1,524(3.8416) (0.50) (0.50) 1,524 (0.0025)+ [(3.8416) (0.50) (0.50)] 5854.5984-0.25 3.81 +[(3.8416) (0.25)] 1,463.6496 4.7704 = 306.8190508 ≈ 307
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