An object travels in a vertical circle of 1.76 m radius. When the object is traveling downward and is 39.0° from its lowest point, its total acceleration is a = (18.5î + 16.2j) m/s2. At this instant, determine the following. (Take the angle 39.0° clockwise from the axis of the circle that intersects the center and the lowest point. Assume that the +x axis is to the right and the +y axis is up along the page.) (a) magnitude of the radial acceleration 22.89 Draw a figure in order to get a good view of the particle, the acceleration vector, and its components. How can you obtain the radial acceleration from the components of the total acceleration? m/s2 (b) magnitude of the tangential acceleration m/s? (c) speed of the object m/s (d) velocity of the object (Express your answer in vector form.) m/s

Physics for Scientists and Engineers with Modern Physics
10th Edition
ISBN:9781337553292
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter6: Circular Motion And Other Applications Of Newton's Laws
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Problem 3P: A car initially traveling eastward turns north by traveling in a circular path at uniform speed as...
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### Problem Statement:

**Context:**
An object travels in a vertical circle of 1.76 m radius. When the object is traveling downward and is 39.0° from its lowest point, its total acceleration is \( \vec{a} = (18.5 \hat{i} + 16.2 \hat{j}) \, \text{m/s}^2 \). At this instant, determine the following. (Take the angle 39.0° clockwise from the axis of the circle that intersects the center and the lowest point. Assume that the +x axis is to the right and the +y axis is up along the page.)

**Questions:**
1. (a) Magnitude of the radial acceleration
2. (b) Magnitude of the tangential acceleration
3. (c) Speed of the object
4. (d) Velocity of the object (Express your answer in vector form.)

---

**Solutions:**

**(a) Magnitude of the radial acceleration:**

\[  \boxed{[22.89]} \times \]

*Note: Draw a figure to get a good view of the particle, the acceleration vector, and its components. How can you obtain the radial acceleration from the components of the total acceleration?*

Unit: \( \text{m/s}^2 \)

---

**(b) Magnitude of the tangential acceleration:**

\[ \boxed{[ \phantom{x} ]}  \\]

Unit: \( \text{m/s}^2 \)

---

**(c) Speed of the object:**

\[ \boxed{[ \phantom{x} ]} \times \]

Unit: \( \text{m/s} \)

---

**(d) Velocity of the object (Express your answer in vector form):**

\[ \vec{v} = \boxed{[ \phantom{x} ]} \]

Unit: \( \text{m/s} \)

---

**Explanation of Diagrams and Figures:**

- A diagram should be drawn that includes the circle of motion, indicating the object's position at 39.0° from the lowest point.
- Mark the direction of the total acceleration vector \(( \vec{a} )\).
- Decompose the total acceleration vector into radial and tangential components.

### Observations:

- A red cross mark suggests an incorrect answer for (a)'s provided value 22.89 \(
Transcribed Image Text:### Problem Statement: **Context:** An object travels in a vertical circle of 1.76 m radius. When the object is traveling downward and is 39.0° from its lowest point, its total acceleration is \( \vec{a} = (18.5 \hat{i} + 16.2 \hat{j}) \, \text{m/s}^2 \). At this instant, determine the following. (Take the angle 39.0° clockwise from the axis of the circle that intersects the center and the lowest point. Assume that the +x axis is to the right and the +y axis is up along the page.) **Questions:** 1. (a) Magnitude of the radial acceleration 2. (b) Magnitude of the tangential acceleration 3. (c) Speed of the object 4. (d) Velocity of the object (Express your answer in vector form.) --- **Solutions:** **(a) Magnitude of the radial acceleration:** \[ \boxed{[22.89]} \times \] *Note: Draw a figure to get a good view of the particle, the acceleration vector, and its components. How can you obtain the radial acceleration from the components of the total acceleration?* Unit: \( \text{m/s}^2 \) --- **(b) Magnitude of the tangential acceleration:** \[ \boxed{[ \phantom{x} ]} \\] Unit: \( \text{m/s}^2 \) --- **(c) Speed of the object:** \[ \boxed{[ \phantom{x} ]} \times \] Unit: \( \text{m/s} \) --- **(d) Velocity of the object (Express your answer in vector form):** \[ \vec{v} = \boxed{[ \phantom{x} ]} \] Unit: \( \text{m/s} \) --- **Explanation of Diagrams and Figures:** - A diagram should be drawn that includes the circle of motion, indicating the object's position at 39.0° from the lowest point. - Mark the direction of the total acceleration vector \(( \vec{a} )\). - Decompose the total acceleration vector into radial and tangential components. ### Observations: - A red cross mark suggests an incorrect answer for (a)'s provided value 22.89 \(
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