An object travels in a vertical circle of 1.43 m radius. When the object is traveling downward and is 28.0° from its lowest point, its total acceleration is a = (18.51 + 16.2ĵ) m/s². At this instant, determine the following. (Take the angle 28.0° clockwise from the axis of the circle that intersects the center and the lowest point. Assume that the +x axis is to the right and the +y axis is up along the page.) (a) magnitude of the radial acceleration m/s² (b) magnitude of the tangential acceleration m/s² (c) speed of the object m/s (d) velocity of the object (Express your answer in vector form.) m/s
Gravitational force
In nature, every object is attracted by every other object. This phenomenon is called gravity. The force associated with gravity is called gravitational force. The gravitational force is the weakest force that exists in nature. The gravitational force is always attractive.
Acceleration Due to Gravity
In fundamental physics, gravity or gravitational force is the universal attractive force acting between all the matters that exist or exhibit. It is the weakest known force. Therefore no internal changes in an object occurs due to this force. On the other hand, it has control over the trajectories of bodies in the solar system and in the universe due to its vast scope and universal action. The free fall of objects on Earth and the motions of celestial bodies, according to Newton, are both determined by the same force. It was Newton who put forward that the moon is held by a strong attractive force exerted by the Earth which makes it revolve in a straight line. He was sure that this force is similar to the downward force which Earth exerts on all the objects on it.
Given,
The radius of the vertical circle is
The angular position of the object from the lowest position is
The total acceleration of the object is
from above expression horizontal component of the total acceleration is
From above expression vertical component of the total acceleration is
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