An object is thrown vertically upward from the surface of a celestial body at a velocity of 18 meters per second. Its distance from the surface at t seconds is given by s(t) = - 0.31 + 18t. a. How fast is the object moving 8 seconds after being thrown? b. How long after the object is thrown does it reach its maximum height? c. How high will the object go? ....

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Chapter1: Units, Trigonometry. And Vectors
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An object is thrown vertically upward from the surface of a celestial body at a velocity of 18 meters per second. Its distance from the surface at t seconds is given by
s(t) = - 0.312 + 18t.
a. How fast is the object moving 8 seconds after being thrown?
b. How long after the object is thrown does it reach its maximum height?
c. How high will the object go?
a. The object's velocity after
seconds is m/sec.
(Round to the nearest tenth as needed.)
Transcribed Image Text:An object is thrown vertically upward from the surface of a celestial body at a velocity of 18 meters per second. Its distance from the surface at t seconds is given by s(t) = - 0.312 + 18t. a. How fast is the object moving 8 seconds after being thrown? b. How long after the object is thrown does it reach its maximum height? c. How high will the object go? a. The object's velocity after seconds is m/sec. (Round to the nearest tenth as needed.)
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