1. Andrew and Kevin decide to try out the physics ideas that they are learning and take their baseball pitching machine and a baseball to a 96 feet tall local building. Based on what they have learned the height, s(t), of a baseball, thrown straight up with an initial speed of 80 feet per second from a rooftop 96 feet high is s(t)=-16t^2+80t+96 where t is the elapsed time that the baseball is in the air. The baseball that is pitched miss the rooftop on their way down and eventually strike the ground.  a) What is the average velocity of a baseball from t=0 to t=2 seconds? b) What is the velocity of the baseball 2 seconds after it is thrown? c) After how many seconds will the velocity of the baseball reach zero?

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1. Andrew and Kevin decide to try out the physics ideas that they are learning and take their baseball pitching machine and a baseball to a 96 feet tall local building. Based on what they have learned the height, s(t), of a baseball, thrown straight up with an initial speed of 80 feet per second from a rooftop 96 feet high is s(t)=-16t^2+80t+96 where t is the elapsed time that the baseball is in the air. The baseball that is pitched miss the rooftop on their way down and eventually strike the ground. 

a) What is the average velocity of a baseball from t=0 to t=2 seconds?

b) What is the velocity of the baseball 2 seconds after it is thrown?

c) After how many seconds will the velocity of the baseball reach zero?

d) What is the velocity of the baseball t seconds after it is thrown? 

e) What is the velocity of the baseball as it passes the roof top on the way down?

Expert Solution
Step 1

As per guidelines , only first 3 subparts are solved here.

Given,

height = 96 feet

initial velocity = 80 feet per second

s(t) = -16t2+80t+96

 

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