An object begins at position x = 0 and moves one-dimensionally along the x-axis with a velocity v expressed as a function of time t according to the graph above. At what time does the object pass through x = 0 again? A: Between 10 s and 20 s B: Between 20 s and 30 s C: At 30 s exactly D: Between 30 s and 40 s E: After 40 s
An object begins at position x = 0 and moves one-dimensionally along the x-axis with a velocity v expressed as a function of time t according to the graph above. At what time does the object pass through x = 0 again? A: Between 10 s and 20 s B: Between 20 s and 30 s C: At 30 s exactly D: Between 30 s and 40 s E: After 40 s
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
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Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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An object begins at position x = 0 and moves one-dimensionally along the x-axis with a velocity v expressed as a function of time t according to the graph above. At what time does the object pass through x = 0 again?
A: Between 10 s and 20 s
B: Between 20 s and 30 s
C: At 30 s exactly
D: Between 30 s and 40 s
E: After 40 s
![The image displays a velocity-time graph for an object's motion. Below is a detailed explanation of the graph:
### Axes:
- **Vertical Axis (y-axis):** Represents velocity \( v \) in meters per second (m/s), ranging from -20 m/s to 20 m/s.
- **Horizontal Axis (x-axis):** Represents time \( t \) in seconds (s), marked from 0 to 40 seconds.
### Graph Description:
1. **Time 0 to 10 seconds:**
- The velocity increases from 0 to 20 m/s, forming a straight, upward slope.
- This indicates constant acceleration.
2. **Time 10 to 20 seconds:**
- The velocity decreases from 20 m/s back to 0 m/s, forming a straight, downward slope.
- This indicates constant deceleration back to rest.
3. **Time 20 to 30 seconds:**
- The velocity continues decreasing to -20 m/s, forming another straight, downward slope.
- This represents a continuation of deceleration past rest to a negative velocity, indicating a change in direction.
4. **Time 30 to 40 seconds:**
- The velocity remains constant at -20 m/s.
- This indicates uniform motion in the reverse direction.
Overall, the graph outlines a sequence of acceleration, deceleration, change in direction, and uniform motion.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F8dd8e58b-180b-4b0d-b22f-f384454462dc%2F7c8a5de2-0587-44d1-879b-71e9bfd439e3%2Fcid80w_processed.png&w=3840&q=75)
Transcribed Image Text:The image displays a velocity-time graph for an object's motion. Below is a detailed explanation of the graph:
### Axes:
- **Vertical Axis (y-axis):** Represents velocity \( v \) in meters per second (m/s), ranging from -20 m/s to 20 m/s.
- **Horizontal Axis (x-axis):** Represents time \( t \) in seconds (s), marked from 0 to 40 seconds.
### Graph Description:
1. **Time 0 to 10 seconds:**
- The velocity increases from 0 to 20 m/s, forming a straight, upward slope.
- This indicates constant acceleration.
2. **Time 10 to 20 seconds:**
- The velocity decreases from 20 m/s back to 0 m/s, forming a straight, downward slope.
- This indicates constant deceleration back to rest.
3. **Time 20 to 30 seconds:**
- The velocity continues decreasing to -20 m/s, forming another straight, downward slope.
- This represents a continuation of deceleration past rest to a negative velocity, indicating a change in direction.
4. **Time 30 to 40 seconds:**
- The velocity remains constant at -20 m/s.
- This indicates uniform motion in the reverse direction.
Overall, the graph outlines a sequence of acceleration, deceleration, change in direction, and uniform motion.
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