An inspector on an assembly line of a refrigerator plant classifieds each refrigerator according to the properties of its enamel.Based on its data, the inspector assigns the probabilities listed in the table below: (in the picture) Assume that no refrigerator has both too much or too little enamel and the only defects of concern are E1, E2, E3. What is the probability that a randomly selected refrigerator has each of the following: (a) A paint defect (b) A paint defect resulting from an improper amount of paint (c) A paint defect resulting from an improper amount of paint and uneven application(edited)
An inspector on an assembly line of a refrigerator plant classifieds each refrigerator according to the properties of its enamel.Based on its data, the inspector assigns the probabilities listed in the table below: (in the picture)
Assume that no refrigerator has both too much or too little enamel and the only defects of concern are E1, E2, E3. What is the
Solution :
Given :
E1 : Too much enamel and P(E1) = 0.04
E2 : Too little enamel and P(E2) = 0.12
E3 : Uneven application and P(E3) = 0.09
E4: No defects noted and P(E4) = 0.82
a) Probability that a paint defect = 1- Probability that no defects noted
= 1 - P(E4)
= 1-0.82
= 0.18
Answer : Probability that randomly selected refrigerator has a paint defect is 0.18.
Trending now
This is a popular solution!
Step by step
Solved in 2 steps