An industrial/organizational psychologist has been consulting with a company that runs weekend job-seeking workshops for the unemployed. She collected data on several issues related to these workshops and, after conducting statistical tests, obtained statistically significant findings. She needs to find a way to evaluate effect size so that she can make recommendations to the company. One of the psychologist’s findings is that one year after the workshop, a sample of 36 job seekers who received training on setting career goals scored an average of 7.3 as measured on a 9-point job-search motivation scale, with a standard deviation of 1.5. The typical job seeker scores 6.1 points. The psychologist finds that the estimated Cohen’s d is , the t statistic is 4.80, and r² is . Using Cohen’s d and Cohen’s guidelines for interpreting the effect size with the estimated Cohen’s d, there is a treatment effect. Using r² and the extension of Cohen’s guidelines for interpreting the effect size using r², there is a treatment effect. (Hint: When using Cohen’s guidelines for interpreting the effect size, if the value lies between two categories, then specify the range covered by both categories, for example, medium to large.) Another one of the psychologist’s findings is that a sample of 121 job seekers who received training on identifying marketable skills worked an average of 6.1 hours per week, with a standard deviation of 1.2. The typical job seeker works 5.7 hours. She finds that the estimated Cohen’s d is , the t statistic is 3.64, and r² is . Using Cohen’s d and Cohen’s guidelines for interpreting the effect size with the estimated Cohen’s d, there is a treatment effect. Using r² and the extension of Cohen’s guidelines for interpreting the effect size with r², there is a treatment effect.

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Description: An industrial/organizational psychologist has been consulting with a company that runs weekend job-seeking workshops for the unemployed. She collected data on several issues related to these workshops and, after conducting statistical tests, obtained

MATLAB: An Introduction with Applications

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An industrial/organizational psychologist has been consulting with a company that runs weekend job-seeking workshops for the unemployed. She collected data on several issues related to these workshops and, after conducting statistical tests, obtained statistically significant findings. She needs to find a way to evaluate effect size so that she can make recommendations to the company.

One of the psychologist’s findings is that one year after the workshop, a sample of 36 job seekers who received training on setting career goals scored an average of 7.3 as measured on a 9-point job-search motivation scale, with a standard deviation of 1.5. The typical job seeker scores 6.1 points.

The psychologist finds that the estimated Cohen’s d is , the t statistic is 4.80, and r² is .

Using Cohen’s d and Cohen’s guidelines for interpreting the effect size with the estimated Cohen’s d, there is a treatment effect. Using r² and the extension of Cohen’s guidelines for interpreting the effect size using r², there is a treatment effect. (Hint: When using Cohen’s guidelines for interpreting the effect size, if the value lies between two categories, then specify the range covered by both categories, for example, medium to large.)

Another one of the psychologist’s findings is that a sample of 121 job seekers who received training on identifying marketable skills worked an average of 6.1 hours per week, with a standard deviation of 1.2. The typical job seeker works 5.7 hours.

She finds that the estimated Cohen’s d is , the t statistic is 3.64, and r² is . Using Cohen’s d and Cohen’s guidelines for interpreting the effect size with the estimated Cohen’s d, there is a treatment effect. Using r² and the extension of Cohen’s guidelines for interpreting the effect size with r², there is a treatment effect.

Expert Solution

Step 1

1) Given that:

$n = 36 \bar{x} = 7.3 s = 1.5 μ = 6.1$

Cohen's d is calculated as:

$Cohen' s d = \frac{\bar{x} - μ}{s} = \frac{7.3 - 6.1}{1.5} = 0.8$

The value of t-statistic = 4.8

Degrees of freedom df = n-1 = 35

So, $r^{2} = \frac{t^{2}}{t^{2} + d f} = \frac{4 . 8^{2}}{4 . 8^{2} + 35} = 0.3969$

The psychologist finds that the estimated Cohen’s d is 0.8, the t statistic is 4.80, and r² is 0.3969

Using Cohen’s d and Cohen’s guidelines for interpreting the effect size with the estimated Cohen’s d, there is a large treatment effect. Using r² and the extension of Cohen’s guidelines for interpreting the effect size using r², there is a large treatment effect.

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