An independent random sample is selected from an approximately normal population with an unknown standard deviation. Find the p-value for the given sample size and test statistic. Also determine if the null hypothesis would be rejected at α = 0.05. (a) n=11,T =1.91
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An independent random sample is selected from an approximately normal population with an unknown standard deviation. Find the p-value for the given
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(a) n=11,T =1.91
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- A sample is selected from a population with A = 150. After a treatment is administered to the individuals, the sample mean is found to be = 140 and the standard deviation is S= 9. If the sample has n = 18 scores, determine whether the sample is sufficient to conclude that the treatment has significant effect. Use a two tail test with a = 0.02. (Assume the population is normally distributed)Let m denote margin of error, n sample size and σ standard deviation. m= zα/2(σn) Solve the above equation for n.Use the t-distribution and the given sample results to complete the test of the given hypotheses. Assume the results come from random samples, and if the sample sizes are small, assume the underlying distributions are relatively normal. Test Ho : HA = Ha VS H. : HA # Hg using the fact that Group A has 8 cases with a mean of 125 and a standard deviation of 18 while Group B has 15 cases with a mean of 118 and a standard deviation of 14. (a) Give the test statistic and thep-value. Round your answer for the test statistic to two decimal places and your answer for the p- value to three decimal places. test statistic = p-value = eTextbook and Media (b) What is the conclusion of the test? Test at a 10% level. O Reject Ho. O Do not reject Ho. eTextbook and Media
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Find the probability that at most 81 favor a charter school using the normal approximation and the table. (Round off to z-values up to 2 decimal places.) P(X 75) - P(Y > a (Z > e. Find the probability that exactly 81 favor a charter school using the normal approximation and the table. (Round off to z-values up to 2 decimal places.) P(X = 81) - P(A sample is selected from a population with A = 150. After a treatment is administered to the individuals, the sample mean is found to be = 140 and the standard deviation is S= 9. If the sample has n = 18 scores, determine whether the sample is sufficient to conclude that the treatment has significant effect. Use a two tail test with a = 0.02. (Assume the population is normally distributed)Suppose in a local Kindergarten through 12th grade (K -12) school district, 49% of the population favor a charter school for grades K through 5. A simple random sample of 144 is surveyed. a. Find the mean and the standard deviation of X of B(144, 0.49). 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(a) Identify the null hypothesis and alternative hypothesis. A. Ho: μ> 749 Ha: ≤749 (claim) D. Ho: μ≤ 720 Ha: μ>720 (claim) B. Ho: μ = 720 Ha: μ#720 (claim) E. Ho: μ#749(claim) Ha: μ = 749 O C. Ho: μ<720 (claim) Ha:μ ≥720 OF. Ho: μ ≥749 (claim) Ha: μ<749We have a random sample of 36 data palrs where the sample mean of the differences is 1.18 and the sample standard devlation of the differences Is 3. Then the sample test statistic Is d = 1.18 Using these values, along with u = 0, we calculate the corresponding t value for the test statistic. 1.18 - 0 V V36 0.065A simple random sample of size n=40 is drawn from a population. The sample mean is found to be 107.6, and the sample standard deviation is found to be 20.2. Is the population mean greater than 100 at the α=0.025 level of significance? Determine the null and alternative hypotheses. H0: mu equals 100μ=100 mu less than 100μ<100 mu equals 100μ=100 mu greater than 100μ>100 mu less than 107.6μ<107.6 mu equals 107.6μ=107.6 mu greater than 107.6μ>107.6 H1: mu greater than 100μ>100 mu less than 100μ<100 mu equals 100μ=100 mu greater than 100μ>100 mu less than 107.6μ<107.6 mu equals 107.6μ=107.6 mu greater than 107.6μ>107.6 Compute the test statistic. t 0t0 t 0t0 z 0z0 = (Round to two decimal places as needed.) Determine the P-value. The P-value is . (Round to three decimal places as needed.) What is the result of the hypothesis test? the null hypothesis because the P-value is the level of significance.…A simple random sample of size n = 40 is drawn from a population. The sample mean is found to be 108.6, and the sample standard deviation is found to be 19.6. Is the population mean greater than 100 at the x = 0.01 level of significance? Determine the null and alternative hypotheses. 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