An ideal polarizer with its transmission axis rotated 30° to the vertical is placed in a beam of unpolarized light of intensity 10 W/m². After passing through the polarizer, what is intensity of the beam? a) 10 W/m² b) 5.0 W/m² c) 8.7 W/m² d) 7.5 W/m²

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**Polarization and Intensity of Light**

**Question:**

An ideal polarizer with its transmission axis rotated 30° to the vertical is placed in a beam of unpolarized light of intensity 10 W/m². After passing through the polarizer, what is the intensity of the beam?

a) 10 W/m²  
b) 5.0 W/m²  
c) 8.7 W/m²  
d) 7.5 W/m²  

**Explanation:**

When unpolarized light passes through a polarizer, the intensity of the light is reduced. The intensity \(I\) of the polarized light after passing through an ideal polarizer can be calculated using Malus's Law, which is given by:

\[ I = I_0 \cdot \cos^2(\theta) \]

where:
- \(I_0\) is the initial intensity of the unpolarized light,
- \(\theta\) is the angle between the light's initial polarization direction and the axis of the polarizer.

For unpolarized light, the initial intensity is reduced by half after passing through the first polarizer:

\[ I' = \frac{I_0}{2} \]

Here, \(I_0 = 10 \, \text{W/m}^2\) and \(\theta = 30^\circ\):

\[ I' = \frac{10 \, \text{W/m}^2}{2} = 5 \, \text{W/m}^2 \]

After the polarizer at 30°, the intensity is:

\[ I = 5 \, \text{W/m}^2 \cdot \cos^2(30^\circ) \]

\[ \cos(30^\circ) = \sqrt{3}/2 \]

\[ I = 5 \, \text{W/m}^2 \cdot \left(\frac{\sqrt{3}}{2}\right)^2  \]

\[ I = 5 \, \text{W/m}^2 \cdot \frac{3}{4}  \]

\[ I = \frac{15}{4} \, \text{W/m}^2 \]

\[ I = 3.75 \, \text{W/m}^2 \]

Since none of the options directly match this result, further calculations should be double-checked,
Transcribed Image Text:**Polarization and Intensity of Light** **Question:** An ideal polarizer with its transmission axis rotated 30° to the vertical is placed in a beam of unpolarized light of intensity 10 W/m². After passing through the polarizer, what is the intensity of the beam? a) 10 W/m² b) 5.0 W/m² c) 8.7 W/m² d) 7.5 W/m² **Explanation:** When unpolarized light passes through a polarizer, the intensity of the light is reduced. The intensity \(I\) of the polarized light after passing through an ideal polarizer can be calculated using Malus's Law, which is given by: \[ I = I_0 \cdot \cos^2(\theta) \] where: - \(I_0\) is the initial intensity of the unpolarized light, - \(\theta\) is the angle between the light's initial polarization direction and the axis of the polarizer. For unpolarized light, the initial intensity is reduced by half after passing through the first polarizer: \[ I' = \frac{I_0}{2} \] Here, \(I_0 = 10 \, \text{W/m}^2\) and \(\theta = 30^\circ\): \[ I' = \frac{10 \, \text{W/m}^2}{2} = 5 \, \text{W/m}^2 \] After the polarizer at 30°, the intensity is: \[ I = 5 \, \text{W/m}^2 \cdot \cos^2(30^\circ) \] \[ \cos(30^\circ) = \sqrt{3}/2 \] \[ I = 5 \, \text{W/m}^2 \cdot \left(\frac{\sqrt{3}}{2}\right)^2 \] \[ I = 5 \, \text{W/m}^2 \cdot \frac{3}{4} \] \[ I = \frac{15}{4} \, \text{W/m}^2 \] \[ I = 3.75 \, \text{W/m}^2 \] Since none of the options directly match this result, further calculations should be double-checked,
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