The average intensity a distance d₁ = 1.6 m from an omni-directional light bulb is l₁ = 1.3 W/m².(a) Write a symbolic expression for the intensity a distance d₂ = 2.5 m from the same bulb,in terms of ₁, d₁ and d₂, and calculate its numeric value.1,₂W/m² (Don't worry about the font -- use 11 for 1.)(b) Calculate the maximum output power of the light bulb.Pmax =W EM waves, like all other waves, are generated a source. The power of a source measures the rate that it radiates EM energy. The energy spreadsoutward as the wave carries it away from the source so the amount crossing a given area decreases with distance.The intensity at a given point measures the rate per unit areathat EM energy is being transported to that point (i.e. received).Intensity = Source Power/Surface AreaThe surface area takes into account the specific details of howenergy spreads outward as it radiates away from the source.A light source that radiates uniformly in all directions like theone shown in the figure is called isotropic or omni-directional.The energy is spread uniformly across spherical surfaces thatare centered on the source so the intensity, , a distance, d,from an isotropic source that with power, P, is given by:Il=P4zd²ObservationPointSurface Area = 4nd²

The average intensity at a distance d1=1.6 m is l1=1.3 W/m.

The average intensity a distance d₁ = 1.6 m from an omni-directional light bulb is 1 = 1.3 W/m². (a) Write a symbolic expression for the intensity a distance d₂ = 2.5 m from the same bulb, in terms of ₁, d₁ and d2, and calculate its numeric value. ₂: (b) Calculate the maximum output power of the light bulb. Pmax = W/m² (Don't worry about the font -- use 11 for ₁.) W

The average intensity a distance d₁ = 1.6 m from an omni-directional light bulb is 1 = 1.3 W/m². (a) Write a symbolic expression for the intensity a distance d₂ = 2.5 m from the same bulb, in terms of ₁, d₁ and d2, and calculate its numeric value. ₂: (b) Calculate the maximum output power of the light bulb. Pmax = W/m² (Don't worry about the font -- use 11 for ₁.) W

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Concept explainers

Electromagnetic Waves

Electromagnetic waves are waves that consist of magnetic field and electric field components perpendicular to each other. These field components are also perpendicular to the direction of propagation of the wave.

Question

The average intensity a distance d₁ = 1.6 m from an omni-directional light bulb is l₁ = 1.3 W/m².
(a) Write a symbolic expression for the intensity a distance d₂ = 2.5 m from the same bulb,
in terms of ₁, d₁ and d₂, and calculate its numeric value.
1,
₂
W/m² (Don't worry about the font -- use 11 for 1.)
(b) Calculate the maximum output power of the light bulb.
Pmax =
W

EM waves, like all other waves, are generated a source. The power of a source measures the rate that it radiates EM energy. The energy spreads
outward as the wave carries it away from the source so the amount crossing a given area decreases with distance.
The intensity at a given point measures the rate per unit area
that EM energy is being transported to that point (i.e. received).
Intensity = Source Power/Surface Area
The surface area takes into account the specific details of how
energy spreads outward as it radiates away from the source.
A light source that radiates uniformly in all directions like the
one shown in the figure is called isotropic or omni-directional.
The energy is spread uniformly across spherical surfaces that
are centered on the source so the intensity, , a distance, d,
from an isotropic source that with power, P, is given by:
Il
=
P
4zd²
Observation
Point
Surface Area = 4nd²

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