7. A vertically polarized beam of light of intensity 100 W/m² passes through two ideal polarizers. The transmission axis of the first polarizer makes an angle of 20.0° with the vertical, and the axis of the second polarizer is at angle 30.0° relative to the second one. What is the intensity of the light after it has passes through both polarizers? a) 22.2 W/m² b) 44.4 W/m² c) 66.2 W/m² d) 78.0 W/m²
7. A vertically polarized beam of light of intensity 100 W/m² passes through two ideal polarizers. The transmission axis of the first polarizer makes an angle of 20.0° with the vertical, and the axis of the second polarizer is at angle 30.0° relative to the second one. What is the intensity of the light after it has passes through both polarizers? a) 22.2 W/m² b) 44.4 W/m² c) 66.2 W/m² d) 78.0 W/m²
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![**Question 7: Polarization of Light**
A vertically polarized beam of light with an intensity of \(100 \, \text{W/m}^2\) passes through two ideal polarizers. The transmission axis of the first polarizer makes an angle of \(20.0^\circ\) with the vertical, and the axis of the second polarizer is at an angle of \(30.0^\circ\) relative to the first one. What is the intensity of the light after it has passed through both polarizers?
a) \(22.2 \, \text{W/m}^2\)
b) \(44.4 \, \text{W/m}^2\)
c) \(66.2 \, \text{W/m}^2\)
d) \(78.0 \, \text{W/m}^2\)
**Analysis:**
This is a classic problem involving Malus's Law, which states that when polarized light passes through a polarizer, the intensity \(I\) of the light transmitted is given by:
\[ I = I_0 \cos^2(\theta) \]
Where:
- \(I_0\) is the initial intensity of the light.
- \(\theta\) is the angle between the light’s initial polarization direction and the axis of the polarizer.
Here, the light initially has an intensity \(I_0 = 100 \, \text{W/m}^2\).
1. **First Polarizer:**
- Angle \(\theta_1 = 20.0^\circ\)
- \[ I_1 = 100 \, \cos^2(20^\circ) \]
2. **Second Polarizer:**
- Angle \(\theta_2 = 30.0^\circ\) relative to the first polarizer's axis.
- \[ I_2 = I_1 \cos^2(30^\circ) \]
Using these calculations, you can find the final intensity of light after passing through both polarizers.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd9a2776d-a528-4478-be0e-235d689690c2%2F6a380355-36b7-442a-97cd-c006c6a03519%2Fi3592t_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Question 7: Polarization of Light**
A vertically polarized beam of light with an intensity of \(100 \, \text{W/m}^2\) passes through two ideal polarizers. The transmission axis of the first polarizer makes an angle of \(20.0^\circ\) with the vertical, and the axis of the second polarizer is at an angle of \(30.0^\circ\) relative to the first one. What is the intensity of the light after it has passed through both polarizers?
a) \(22.2 \, \text{W/m}^2\)
b) \(44.4 \, \text{W/m}^2\)
c) \(66.2 \, \text{W/m}^2\)
d) \(78.0 \, \text{W/m}^2\)
**Analysis:**
This is a classic problem involving Malus's Law, which states that when polarized light passes through a polarizer, the intensity \(I\) of the light transmitted is given by:
\[ I = I_0 \cos^2(\theta) \]
Where:
- \(I_0\) is the initial intensity of the light.
- \(\theta\) is the angle between the light’s initial polarization direction and the axis of the polarizer.
Here, the light initially has an intensity \(I_0 = 100 \, \text{W/m}^2\).
1. **First Polarizer:**
- Angle \(\theta_1 = 20.0^\circ\)
- \[ I_1 = 100 \, \cos^2(20^\circ) \]
2. **Second Polarizer:**
- Angle \(\theta_2 = 30.0^\circ\) relative to the first polarizer's axis.
- \[ I_2 = I_1 \cos^2(30^\circ) \]
Using these calculations, you can find the final intensity of light after passing through both polarizers.
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